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3 years ago

12

-- {(-7, 2), (3,5), (8,4), (-6,5), (-2,3)} Domain:

1 answer:

8090 [49]3 years ago

8 0

Answer:

no solution

Step-by-step explanation:

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Help with this math homework please

labwork [276]

Answer:

When you add an irrational and rational number the sum becomes irrational as well.

Alright so let's pick an irrational number I'm gonna say pi. A rational number, let's go with 1. Pi plus 1 is about 4.14 rounded to the nearest hundredth. How about multiplying? It's pi still cause anything times one equals itself.

5 0

3 years ago

Sup can someone help me with dis

attashe74 [19]

Answer:

8,100,20

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

5. Select all the expressions that represent the area of the shaded rectangle.

zlopas [31]

Answer:

Step-by-step explanation:

what shaded rectangle?

5 0

3 years ago

Please help and thank you

Brut [27]

Answer:

A

Step-by-step explanation:

In these kind of functions: <em>adding outside of the absolute value moves the graph up</em>, <em>adding inside moves it to the left</em>.

So, since it is moved 4 to the right, there will be a <em>- 4 inside</em>.

Also, since it moves 6 up, there is a <em>+ 6 outside</em>.

The only equation to do so is A.

8 0

4 years ago

Calculate the angle between (2,2,4) and (2,-1,1). The result is a familiar angle, so the answer is to be given exactly.

andrew-mc [135]

Answer:

The angle between $(2,2,4)$ and $(2,-1,1)$ is 60º.

Step-by-step explanation:

From linear algebra, we can determine the angle between both vectors by definition of dot point:

$\cos \theta = \frac{\vec u\bullet \vec v}{\|\vec u\|\cdot \| \vec v\|}$ (1)

Where:

$\vec u$ , $\vec v$ - Vectors.

$\|\vec u\|$ , $\|\vec v\|$ - Norms of vectors.

$\theta$ - Angle between vectors, measured in sexagesimal degrees.

If we know that $\vec u = (2,2,4)$ and $\vec v = (2,-1,1)$ , then angle between vectors is:

$\|\vec u\| = \sqrt{\vec u\bullet \vec u}$ (2)

$\|\vec u\| = \sqrt{2^{2}+2^{2}+4^{2}}$

$\|\vec u\| \approx 4.899$

$\|\vec v\| = \sqrt{\vec v\bullet \vec v}$ (3)

$\|\vec v\| = \sqrt{2^{2}+(-1)^{2}+1^{2}}$

$\|\vec v\| \approx 2.450$

$\vec u \bullet \vec v = (2,2,4)\bullet (2,-1,1)$

$\vec u \bullet \vec v = 4-2+4$

$\vec u \bullet \vec v = 6$

$\cos \theta = \frac{6}{(4.899)\cdot (2.450)}$

$\cos \theta = 0.5$

$\theta = 60^{\circ}$

The angle between $(2,2,4)$ and $(2,-1,1)$ is 60º.

6 0

3 years ago