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4 years ago

Learn multiplication and division

Mathematics

1 answer:

vaieri [72.5K]4 years ago

4 0

multiplication is for example 10×500=5,000
division is for example 5,000÷10=500

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2n-3/5=5 solve for n

dezoksy [38]

N=14/5 thats the answer.

3 0

3 years ago

Read 2 more answers

1. Wendy wants to find the width, AB, of a river. She walks along the edge of the river 300 ft and marks point C. Then she walks

Ierofanga [76]

It can be deduced that the triangles are similar because the three internal angles are equal for both triangles.

<h3>How to solve the triangle?</h3>

It should be noted that the triangles are similar because the three internal angles are equal.

In this case, the ratio of the corresponding sides are equal and the corresponding angles are congruent.

The width of the river will be:

300/80 = AB/50

AB = (300 × 50)/80

AB = 187.50 feet.

Learn more about triangles on:

brainly.com/question/17335144

7 0

3 years ago

otez555 [7]

The function appears to be L(legos) = T(tower)^3

L = T^3

This checks out for t =1,2,3,4

The 100th tower would have 100^3 legos.

100^3 = 1,000,000.

The 100th tower would have 1 million cubes

8 0

3 years ago

I have a math question it is... what is g - 3/7 = 2/7 ?

stira [4]

g - 3/7 = 2/7 is an equation.

$\displaystyle\bf\\g-\frac{3}{7}=\frac{2}{7}\\ \\g=\frac{2}{7}+\frac{3}{7}=\frac{2+3}{7}=\frac{5}{7}\\\\\boxed{\bf g=\frac{5}{7}}$

6 0

3 years ago

A null hypothesis is that the mean nose lengths of men and women are the same. The alternative hypothesis is that men have a lon

algol [13]

Answer:

b. There is not enough evidence to say that the populations of men and women have different mean nose lengths.

See explanation below.

Step-by-step explanation:

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the means for the two groups are different (men have longer mean nose length than women), the system of hypothesis would be:

Null hypothesis: $\mu_{men} \leq \mu_{women}$

Alternative hypothesis: $\mu_{men} > \mu_{women}$

Assuming that we know the population deviations for each group, for this case is better apply a z test to compare means, and the statistic is given by:

$z=\frac{\bar X_{men}-\bar X_{women}}{\sqrt{\frac{\sigma^2_{men}}{n_{men}}+\frac{\sigma^2_{women}}{n_{women}}}}$ (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Let's assume that the calculated statistic is $z_{calc}$

Since is a right tailed test test the p value would be:

$p_v =P(Z>z_{calc})=0.225$

And we know that the p value is 0.225. If we select a significance level for example 0.05 or 0.1 we see that $p_v >\alpha$

And on this case we have enough evidence to FAIl to reject the null hypothesis that the means are equal. So then the best conclusion would be:

b. There is not enough evidence to say that the populations of men and women have different mean nose lengths.

8 0

3 years ago