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marin [14]
3 years ago
14

Suppose that $g(x)=f^{-1}(x)$. If $g(-15)=0$, $g(0)=3$, $g(3)=9$ and $g(9)=20$, what is $f(f(9))$?

Mathematics
1 answer:
never [62]3 years ago
8 0

Answer:

0

Step-by-step explanation:

\text{If } g(x)=f^{-1}(x);$ and:$\\g(-15)=0,$  g(0)=3,  g(3)=9,  g(9)=20

We are to determine the value of f(f(9)).

Now:

g(0)=f^{-1}(0)=3\\g(3)=f^{-1}(3)=9

From:

g(3)=f^{-1}(3)=9\\f(9)=3

From:

g(0)=f^{-1}(0)=3\\f(3)=0

Therefore:

f(f(9))=f(3)=0

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a rectangle has a width of 4 cm and a length of 8cm is scaled by a factor of 6.what are the side lengths of the scaled copy
vichka [17]

Answer:

\huge\boxed{\text{Width: } 24 \ \ \ \text{Length: } 32}

Step-by-step explanation:

When we scale an object by a scale factor, the side lengths become the scale factor times bigger than the previous sides. Therefore, with a scale factor of 6, the side lengths would be multiplied by 6.

4 \cdot 6 = 24\\\\4 \cdot 8 = 32

Hope this helped!

6 0
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Find the average rate of change of the function below over the interval (-4,-1).
babymother [125]

Answer:

-2

Step-by-step explanation:

\frac{f(b)-f(a)}{b-a}\\ \\=\frac{f(-1)-f(-4)}{-1-(-4)}\\ \\=\frac{-4-2}{-1+4}\\ \\=\frac{-6}{3}\\ \\=-2

Therefore, the average rate of change over the interval [-4,-1] is -2.

5 0
2 years ago
Assignment The operation teeter is defined on the set T= { 2, 3, 5, 7 } by x teeter y=[x+y+xy) mod.8 a - Construct mod.8 table f
rosijanka [135]

Answer:

Case A) tau_net = -243.36 N m, case B)    tau_net = 783.36 N / m,      tau_net = -63.36 N m,  case C)  tau _net = - 963.36 N m,

Explanation:

For this exercise we use Newton's relation for rotation

        Σ τ  = I α

In this exercise the mass of the child is m = 28.8, assuming x = 1.5 m, the force applied by the man is F = 180N

we will assume that the counterclockwise turns are positive.

case a

        tau_net = m g x - F x2

         tau_nett = -28.8 9.8 1.5 + 180 1

        tau_net = -243.36 N m

in this case the man's force is downward and the system rotates clockwise

case b

2 force clockwise, the direction of

the force is up

         tau_nett = -28.8 9.8 1.5 - 180 2

         tau_net = 783.36 N / m

in case the force is applied upwards

3) counterclockwise

       tau_nett = -28.8 9.8 1.5 + 180 2

        tau_net = -63.36 N m

system rotates clockwise

case c

2 schedule

tau_nett = -28.8 9.8 1.5 - 180 3

tau _net = - 963.36 N m

3 counterclockwise

      tau_nett = -28.8 9.8 1.5 + 180 3

      tau_net = 116.64 Nm

the sitam rotated counterclockwise

<h3><u><em>Cr: moya1316</em></u></h3>
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1 year ago
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