Let Universal set U = {1, 2, 3, 4, 5, 6, 7, 8}, A' = {2,5, 6, 7}, A N B = {1,3,4}
1 answer:
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Answer:
No; Because g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R
Step-by-step explanation:
Assuming: the function is in [0,1]
And rewriting it for the sake of clarity:
Does there exist a differentiable function g : [0, 1] →R such that g'(x) = f(x) for all g(x)=x² ∈ [0, 1]? Justify your answer
1) A function is considered to be differentiable if, and only if both derivatives (right and left ones) do exist and have the same value. In this case, for the Domain [0,1]:
2) Examining it, the Domain for this set is smaller than the Real Set, since it is [0,1]
The limit to the left
g'(x)=f(x) then g'(0)=f(0) and g'(1)=f(1)
3) Since g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R
Because this is the same as to calculate the limit from the left and right side, of g(x).
This is what the Bilateral Theorem says:
Solution:
Population in the city= 10,000
As genetic condition affects 8% of the population.
8 % of 10,000
As, it is also given that, there is an error rate of 1% for condition (i.e., 1% false negatives and 1% false positives).
So, 1% false negatives means out of 800 tested who are found affected , means there are chances that 1% who was found affected are not affected at all.
So, 1% of 800
Also, 1% false positives means out of 10,000 tested,[10,000-800= 9200] who are found not affected , means there are chances that 1% who was found not affected can be affected also.
So, 1% of 9200
1. Has condition Does not have condition totals = 800
2. Test positive =92
3. Test negative =8
4. Total =800 +92 +8=900
5. Probability (as a percentage) that a person has the condition if he or she tests positive= As 8% are found positive among 10,000 means 9200 are not found affected.But there are chances that out of 9200 , 1% may be affected
that is Probability equal to 0.01 or 1%.