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3 years ago

I need help bc I don’t have a calculator

Mathematics

1 answer:

kari74 [83]3 years ago

7 0

Answer:

B is correct

Step-by-step explanation:

I think you don't need a calculator here. :) Try to figure out next time!

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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Katena32 [7]

Answer:

(a)

$5^{-3}=\frac{1}{125}$

(b)

$-5^{-3}=-\frac{1}{125}$

(c)

$(-5^{-3})^{-1}=-125$

(d)

$(-5^{-3})^{0}=1$

Step-by-step explanation:

(a)

$5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$5^{-3}=\frac{1}{5^3}$

$5^{-3}=\frac{1}{5\times 5\times 5}$

$5^{-3}=\frac{1}{125}$ ........Answer

(b)

$-5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$-5^{-3}=-\frac{1}{5^3}$

$-5^{-3}=-\frac{1}{5\times 5\times 5}$

$-5^{-3}=-\frac{1}{125}$ ........Answer

(c)

$(-5^{-3})^{-1}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{-1}=(-5)^{-3\times -1}$

$(-5^{-3})^{-1}=(-5)^3$

$(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)$

$(-5^{-3})^{-1}=-125$ ........Answer

(d)

$(-5^{-3})^{0}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{0}=(-5)^{-3\times 0}$

$(-5^{-3})^{-1}=(-5)^0$

we can use property

$a^0=1$

$(-5^{-3})^{0}=1$ ........Answer

4 0

2 years ago

A homeowner is installing a swimming pool. You have been asked to install a circuit to operate a 600-watt underwater light and a

insens350 [35]

Answer:

The answer is given below

Step-by-step explanation:

The loads in the circuit are continuous duty, so the circuit can only loaded to 80% of its current rating.

Calculate 80% current rating of the circuit breaker.

Icb = [ 80/100] (20 A)

= (O.8) (20 A )

= 16 A

Now we assume that the value of supply voltage is 120 V

Now we will calculate current flows via under water light which will be taken as Load 1

Ii = 500 W/120 V

= 4.167 A

Current via the circulating pump which will be taken as Load 2 IS 8.5 A

I = load1 + load 2

= 4.167 A + 8.5 A

= 12.67 A

The total current in the circuit obtained which is less than the circuit breaker rating current. Therefore, the power can be operated for both the loads.

3 0

3 years ago

I need help with which equations represents proportional relationships

OLga [1]

Answer:

x=1/4y

Step-by-step explanation:

Step 1: You flip the equation

4x=y

Step 2: Divide both sides by 4

4x/4 = y/4

x=1/4y

8 0

3 years ago

Can someone tell me how to do it, i have more problems like this

BigorU [14]

Answer:

$\large\boxed{\dfrac{7n}{30}=\dfrac{7}{30}n}$

Step-by-step explanation:

$\dfrac{2n}{5}+\left(-\dfrac{n}{6}\right)=\dfrac{2n}{5}-\dfrac{n}{6}$

To subtract both fractions we need a common denominator.

$LCD=(5)(6)=30$

$\dfrac{2n}{5}=\dfrac{2n\cdot6}{5\cdot6}=\dfrac{12n}{30}\\\\\dfrac{n}{6}=\dfrac{n\cdot5}{6\cdot5}=\dfrac{5n}{30}$

Therfore

$\dfrac{2n}{5}-\dfrac{n}{6}=\dfrac{12n}{30}-\dfrac{5n}{30}=\dfrac{12n-5n}{30}=\dfrac{7n}{30}=\dfrac{7}{30}n$

4 0

3 years ago

Two trains leave stations 75 miles apart at the same time heading toward one another on parallel tracks. train a is traveling 60

KATRIN_1 [288]

The distance between them is 75 miles
after 1 hour the train will go 125 miles
125 miles.....1 hour
75 miles..........x hour
x=75/125=75/125*60=36 minutes

d is the answer

8 0

3 years ago