Answer: The required probability of selecting 1 red apple and 2 yellow apples is 36.36%.
Step-by-step explanation: We are given that a bag contains 6 red apples and 5 yellow apples out of which 3 apples are selected at random.
We are to find the probability of selecting 1 red apple and 2 yellow apples.
Let S denote the sample space for selecting 3 apples from the bag and let A denote the event of selecting 1 red apple and 2 yellow apples.
Then, we have
Therefore, the probability of event A is given by
Thus, the required probability of selecting 1 red apple and 2 yellow apples is 36.36%.
3600000, 3600000, 3600000 ur answer is <span>3600000</span>
Answer:
Step-by-step explanation: multiply 4 by 12 then 4 by 3 then 4 by 9.
Answer:
<h3>2x+2y = 100</h3>
Step-by-step explanation:
Total number of points in the test = 100points
If the test has x questions worth 2 points apiece, then the total number of points for x questions with 2 points each will be 2 * x i.e 2x........ 1
Also, if y questions worth 4 points apiece then the total number of points for y questions with 4 points each will be 4 * x i.e 4x ....... 2
Total points = eqn 1 + eqn 2
100 = 2x+ 2y
Rearrange
2x+2y = 100
Hence an equation in Standard Form that would model this situation is 2x+2y = 100
