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AveGali [126]
3 years ago
9

What number can be written as 3 hundreds 7 tens 5 ones?

Mathematics
1 answer:
algol133 years ago
6 0
I believe the answer is 375
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can anyone explain the a+b+c or is it a+b=c? i don't know.....can someone please explain it to me? Pls no links
Ludmilka [50]
It’s a plus b equals c
8 0
3 years ago
Read 2 more answers
Question is in the picture<br>please help
LiRa [457]

When given the graph of a function, the domain would include all the points that there is a graph. The strategy is to find what <em>is not</em> included.

What we are looking for are points of discontinuity. Think of it as when you remove your pencil from the paper.

From left to right, the graph stops at x = -3. So anything less than -3 is in the domain. Next, the graph starts up again at x =-1 after an asymptote (the vertical dashed lines). This piece goes to x = 4. So our domain is from -1 to 4.

Lastly, there's a jump from 4 to 5 and the graph goes on again. After 5, we take all the stuff more than it. So x > 5 is in the domain.

So x < -3, - 1 < x < 4, and x > 5 appears to be our domain. However, end points needed to be checked to see if we include them or not. Again we go left to right.

At x = -3 there is a filled (or closed) circle and that means we include -3.

At x = -1 there is an asymptote. Asymptotes are things you get close to but don't get to. (Think of it as the "I'm Not Touching" game you play on car trips.) So we exclude -1.

At x = 4 there is an unfilled (or open) circle and that means we exclude 4.

At x = 5 there is a filled circle so we include 5.

Now we refine our domain for the endpoints.

x ≤ -3, -1 < x < 4, x ≥ 5 is our domain.

The problem gives us intervals, and we gave it in inequalities. When we include an endpoint we use brackets - [ and } and when we exclude and endpoint we use parentheses - ( and ). Let's go back to x ≤ -3. Anything less works, and -3 is included (closed circle). That interval is (-∞, -3]. Next is the piece between -1 and 4. Since both are excluded, (-1,4) is our interval. We include 5 to write x ≥5 as the interval [5,∞).

Put the bolded ones all together and use the union, ∪, symbol to connect them, since something on the graph could be in any piece.

Our domain is (-∞, -3] ∪(-1,4) ∪ [5,∞).

5 0
4 years ago
Calculate the gradient of the line using rise/run method.
Lapatulllka [165]

Given:

The graph of line.

To find:

The gradient of the line using rise/run method.

Solution:

We know that the gradient of a line is also known as slope.

Slope=\dfrac{Rise}{Run}

Consider the two intercepts, then rise is distance between origin and y-intercept and run is the distance between origin and the x-intercept. But rise must be negative because the value of y decreased from 3 to 0.

Rise=-3

Run=2

Now,

Slope=\dfrac{Rise}{Run}

Slope=\dfrac{-3}{2}

The gradient of the line is -\dfrac{3}{2}.

Therefore, the correct option is C.

8 0
3 years ago
Someone Explain to me how 5. Is valid ???
vichka [17]

This is valid through the law of syllogism. If you swap lines 1 and 2, then you'll have this argument:

If I step on a beehive, then I will get stung.

If I get stung by a bee, then it will hurt.

Therefore, if I step on a beehive, then it will hurt

------------------

So it's like connecting a chain together. Point A (stepping on the hive), leads to point B (getting stung), which leads to point C (getting hurt). We can take a shortcut to bypass point B to jump from A to C in one step. Check out the attached image for a visual of what I'm referring to.

6 0
3 years ago
1. What is a perfect square? 2. What is the square root of 4x²? 3. What is the square root of 25? 4. Factor 4x² + 20x + 25.
Ulleksa [173]

Answer:

Step-by-step explanation:

1) A perfect square is a whole number which is a product of a smaller whole number and itself. Examples of perfect squares are

4(2 × 2)

9(3 × 3)

16(4 × 4)

25(5 × 5)

36(6 × 6)

2) Square root of 4x² is 2x(product of square root of 4 and square root of x²)

3) square of 25 is 5

4) 4x² + 20x + 25

The general formula for solving quadratic equations is expressed as

x = [- b ± √(b² - 4ac)]/2a

From the equation given,

a = 4

b = 20

c = 25

Therefore,

x = [- 20 ± √(20² - 4 × 4 × 25)]/2 × 4

x = [- 20 ± √(400 - 400)]/8

x = [- 20 ± 0]/8

x = - 20/8

x = - 2.5

3 0
3 years ago
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