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jeka57 [31]
2 years ago
10

Erin is making a jewelry box of wood in the shape of a rectangular prism. The jewelry box

Mathematics
1 answer:
Degger [83]2 years ago
3 0
He spend $255 to paint the jewelry
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Write in slope intercept form of the equation of a line passing through (-1,4) and perpendicular to y=x-5.
andrew11 [14]

Answer:

y=-x+3

Step-by-step explanation:

The general slope-intercept equation of a line is y=mx+b where m is the slope and b represents the y intercept. y and x are simply a point the line passes through. In this case, y=x-5, meaning m=1 and b=-5.

In order to find the perpendicular slope, we should take the current slope's <u>negative reciprocal</u>. We have:

-\frac{1}{1} =\\-1

Therefore, our perpendicular slope is -1. We now have equation:

y=-x+b

We can plug in the known values of the point (-1,4) to solve for b.

4=(-1)*(-1)+b\\4=1+b\\b=3

If we now put what we found together, we have equation

y=-x+3

<em>I hope this helps! Let me know if you have any further questions :)</em>

7 0
3 years ago
Find the perimeter of a quadrilateral with vertices at C (−2, 1), D (2, 4), E (5, 0), and F (1, −3).
antoniya [11.8K]

The perimeter of the quadrilateral with vertices at C (−2, 1), D (2, 4), E (5, 0), and F (1, −3) is 20units.

Option C) is the correct answer.

<h3>What a quadrilateral?</h3>

A quadrilateral is simply a polygon with four sides, four angles, and four vertices.

To get the perimeter, we simply add the values of the four side.

Given that;

The vertices are at C (−2, 1), D (2, 4), E (5, 0), and F (1, −3).

To get the dimension between the given coordinates, we use;

 d = √((x2 -x1)² +(y2 - y1)²)

For length CD, DE, EF and FC

CD = √((2 - (-2))² + (4 - 1)²) = √( 16+9) = √25 = 5

DE = √((5 - 2)² + (0 - 4)²) = √( 9+16) = √25 = 5

EF = √((1 - 5)² + (-3 - 0)²) = √( 16+9) = √25 = 5

FC = √((-2 - 1)² + ( 1 - (-3))²) = √( 9+16) = √25 = 5

Perimeter of the quadrilateral = CD + DE + EF + FC

Perimeter of the quadrilateral = 5 + 5 + 5 + 5

Perimeter of the quadrilateral = 20units

Therefore, the perimeter of the quadrilateral with vertices at C (−2, 1), D (2, 4), E (5, 0), and F (1, −3) is 20units.

Option C) is the correct answer.

Learn more about area of rectangle here: brainly.com/question/27612962

#SPJ1

6 0
2 years ago
Read 2 more answers
The sum of two numbers is 14. When one number is added to twice the other number, the result is 25. Find the numbers
ELEN [110]

Let x and y be the two numbers. We have:

\begin{cases}x+y=14\\x+2y=25\end{cases}

Subtract the first equation from the second to get

y=11

And deduce

x+11=14 \iff x=3

The two numbers are 3 and 11.

5 0
2 years ago
Monique has 2 hours to complete 3 homework assignments.She wants to spend the same amount of time on each assignment.How meany m
Xelga [282]
3÷2= 1.5

To make sure if it's correct,
1.5
x2
__
3.0
4 0
2 years ago
Obtain the general solution to the equation. (x^2+10) + xy = 4x=0 The general solution is y(x) = ignoring lost solutions, if any
alukav5142 [94]

Answer:

y(x)=4+\frac{C}{\sqrt{x^2+10}}

Step-by-step explanation:

We are given that a differential equation

(x^2+10)y'+xy-4x=0

We have to find the general solution of given differential equation

y'+\frac{x}{x^2+10}y-\frac{4x}{x^2+10}=0

y'+\frac{x}{x^2+10}y=4\frac{x}{x^2+10}

Compare with

y'+P(x) y=Q(x)

We get

P(x)=\frac{x}{x^2+10}

Q(x)=\frac{4x}{x^2+10}

I.F=e^{\int\frac{x}{x^2+10} dx}=e^{\frac{1}{2}ln(x^2+10)}

e^{ln\sqrt(x^2+10)}=\sqrt{x^2+10}

y\cdot \sqrt{x^2+10}=\int \frac{4x}{x^2+10}\times \sqrt{x^2+10} dx+C

y\cdot \sqrt{x^2+10}=\int \frac{4x}{\sqrt{x^2+10}}+C

y\cdot \sqrt{x^2+10}=4\sqrt{x^2+10}+C

y(x)=4+\frac{C}{\sqrt{x^2+10}}

6 0
3 years ago
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