(m^4 + m^3 + 4) + (-5m^4 + 4m + 1) =
m^4 + (-5m^4) + m^3 + 4m + 4 + 1 =
-4m^4 + m^3 + 4m + 5
The answer is B
Fluid ounces are a unit of capacity
<span>Formula: H(t) = 56t – 16t^2
</span>
H(t) = - 16t^2 + 56t
<span><span>A.
</span>What is the height of the ball after 1 second? H
(1) = 56(1) – 16(1) ^2 = 40 pt.</span>
<span><span>B.
</span>What is the maximum height? X = - (56)/2(- 16) =
1.75 sec h (1.75) = 56(1.75) – 16(1.75) ^2 h (1.75) = 49ft.</span>
<span><span>C.
</span><span>After how many seconds will it return to the
ground? – 16t^2 + 56t = 0 - 8t =0 t = 0</span></span>
<span><span>-
</span><span>8t (2 + - 7) = 0 2t – 7 = 0 t = 7/2
Ans: 3.5 seconds</span></span>
Answer:
He would need 42 cm *or 14cm
Step-by-step explanation:
28/4 is 7
that means that he used 7 cm of tape per present
6 x 7 is 42
that means that he would need 42 cm of tape
4 to 28
6 to 42
*If he already has 4 presents done and he needs to 2 more present then he would need 14 cm, 2 x 7 is 14
