Answer:
The simplified form of the given expression is
Step-by-step explanation:
Here, the given expression is:
Now to simplify the given expression, perform operations on LIKE TERMS:
We get:
Hence the simplified form of the given expression is
If you mean to say to find the 11th term, then know that this is an arithmetic sequence (where you have a common difference).
The common difference in this case is -2.
The formula for finding any term in an arithmetic sequence (specifically the explicit formula) is:
where a_n is the term, a_1 is the first term, n is the term number (position) and d is the common difference.
Let's substitute the corresponding values to the formula.
The 11th term is -17.
By the Hypotenuse Leg theorem, the two triangles are congruent. That is, ΔBXA ≅ ΔBYA
From the question, we are to prove that ΔBXA ≅ ΔBYA
From the Hypotenuse Leg theorem which states that "two right triangles are congruent if the hypotenuse and one leg of one right triangle are congruent to the other right triangle's hypotenuse and leg side".
From the given information,
BX ⊥ XA.
ΔBXA is right triangle with hypotenuse AB
Also,
BY ⊥ YA.
ΔBYA is right triangle with hypotenuse AB
∴ The hypotenuses of the triangles are congruent
Also, from the given information,
XA is congruent to YA
XA and YA are the legs of the right triangles.
Hence, by the Hypotenuse Leg theorem, the two triangles are congruent. That is, ΔBXA ≅ ΔBYA
Learn more on Congruent triangles here: brainly.com/question/27983954
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