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KiRa [710]
3 years ago
9

Dawn bought 12 grams of chocolate. she ate half of the chocolate. How many grams of chocolate did she eat?

Mathematics
2 answers:
andre [41]3 years ago
7 0
Half of twelve is six.

She ate 6 grams.
Nookie1986 [14]3 years ago
3 0
6 grams. you just divide it in half.
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Use the decimals 2.47, 9.57, and 7.1 to write two different addition facts and two different subtraction facts
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James had $400 in his bank account. After
balandron [24]

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C

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2 years ago
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For a data set of the pulse rates for a sample of adult? females, the lowest pulse rate is 39 beats per? minute, the mean of the
Zarrin [17]

Answer:

a) The difference is of 35 beats per minute.

b) So 3.07 standard deviations below the mean.

c) Z = -3.07.

Step-by-step explanation:

Z-score:

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:

Mean \mu = 74, standard deviation \sigma = 11.4

a. What is the difference between the pulse rate of 39 beats per minute and the mean pulse rate of the? females?

39 - 74 = -35

The difference is of 35 beats per minute.

b. How many standard deviations is that? [the difference found in part? (a)?

|Z| when X = 39. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{39 - 74}{11.4}

Z = -3.07

|Z| = 3.07

So 3.07 standard deviations below the mean.

c. Convert the pulse rate of 39 beats per minutes to a z score.

From item b. above, Z = -3.07.

5 0
2 years ago
Complete this table to show the sample space for each roll in the game
leva [86]

I'm assuming you only need help with part B. If that's the case, then all we do is add up the values outside of the table to get the inner cell results. For example, in row 1, column 1, we have 1's outside. They add to 1+1 = 2. So we'll have 2 in the first row and first column of the table. The other cells are computed in this way. In figure 1 (see attached image), I show the intermediate step of adding. Then in figure 2, I actually add up the values and show the final result of what the table will look like when all said and done. Take note of the color coding to help see how the values match up for each inner cell of the table. The color coding is optional.

------------------------------------------------------------------------------------------------------------

Edit: 

Part C -- Part 1) Probability of rolling double sixes


There are five copies of "6" in the table (see figure 2 of the attached image) out of 36 total possibilities. How did I get 36? It's the result of multiplying 6*6. This is because there are 6 faces per die. As the table shows, there are 6 rows and 6 columns giving 36 cells total.


So we divide the number of times "6" shows up (5 times) out of the number of total possibilities (36 total) to get: 5/36 = 0.1389 = 13.89%


Answer as a fraction: 5/36

Answer as a decimal: 0.1389

Answer as a percent: 13.89%

The decimal and percent forms are approximate

---------------------------------------------


Part C -- Part 2) Probability of rolling doubles


To roll doubles, all we need to do is roll the same number twice on each die. In other words, we have "twin values" so to speak. Back in part 1 above, we dealt with just '6's showing up twice. There are other doubles as well


The doubles possibilities are: 

1 and 1

2 and 2

3 and 3

4 and 4

5 and 5

6 and 6


Each combo listed above only shows up once. So we have 6 instances where we have doubles (one instance per side of the die). This is out of 36 total


Divide the values mentioned: 6/36 = 1/6 = 0.1667 = 16.67%


Answer as a fraction: 1/6

Answer as a decimal: 0.1667

<span>Answer as a percent: 16.67%</span>

The decimal and percent forms are approximate

7 0
2 years ago
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