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QveST [7]
2 years ago
11

Please solve all the questions!!! :) will mark brainliest

Mathematics
2 answers:
enot [183]2 years ago
8 0

Step-by-step explanation:

< A = 4x

< B = 3x - 3°

<C = 5x + 3°

Solving for x

< A +<B + <C = 180° {Being sum of angles of triangle }

4x + 3x - 3 ° + 5x + 3° = 180°

12x = 180°

x = 180° / 12

x = 15°

Measure of <A

= 4 * 15°

= 60°

Measure of < B

= 3 * 15° - 3°

= 42°

Measure of < C

= 5* 15° + 3°

= 78°

Hope it will help :)❤

iVinArrow [24]2 years ago
8 0

Answer:

solve for x = 15

Determine the measure of <A = 60

Determine the measure of <B = 42

Determine the measure of <C = 78

hope this helps :)

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What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?
Natasha2012 [34]

Answer:

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Step-by-step explanation:

We have been a quadratic equation:

2x^2-10x-3

We need to find the zeroes of quadratic equation

We have a formula to find zeroes of a quadratic equation:

x=\frac{b^2\pm\sqrt{D}}{2a}\text{where}D=\sqrt{b^2-4ac}

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On comparing general equation with b given equation we get

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On substituting the values in formula we get

D=\sqrt{(-10)^2-4(2)(-3)}

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Now substituting D in  x=\frac{b^2\pm\sqrt{D}}{2a} we get

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Therefore, x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}



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