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3 years ago

HELPPPPOO ASAPPPP After listening to a speech, how do you personally

Mathematics

2 answers:

zlopas [31]3 years ago

3 0

Broseph, it’s just asking you how you personally feel after a good speech. There’s no wrong answers.

Rama09 [41]3 years ago

3 0

it's your choice, there are no wrong answers :/

You might be interested in

There are 550 people at the school carnival.

Svet_ta [14]

Answer:

70% of the people at the fair are students

165 people are on the ride

Step-by-step explanation:

In order to find a percentage, take the fraction given, 385/550, and divide the numerator, 385, and divide it by the denominator, 550. Once completing this, we get 0.7

Next, we multiply the result by 100, and get 70, thus, 385 is 70% of 550.

To find how many people 30% of 550 is, we take the percentage and put it in a fraction with the denominator being 100(changes with size of fraction like a decimal, 300 would be over a denominator of 1000)

With 30/100, we then multiply by 550 with the equation looking like this:

30/100*550/1

Once we finish multiplying(typically using a calculator, although you can do it manually) we get 165, the value of how many people are on rides out of the total 550.

4 0

3 years ago

Whichhhhh<br> oneeeeeeeeeeeee

Nostrana [21]

Answer:

Step-by-step explanation:

the slope of A is 1/2 which is greater than that of B

6 0

2 years ago

Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)

viktelen [127]

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}$

The first line segment can be parameterized by $\mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle$ with $0\le t\le1$ . Denote this first segment by $C_1$ . Then

$\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt$
$=108$

The second line segment ( $C_2$ ) can be described by $\mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle$ , again with $0\le t\le1$ . Then

$\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt$
$=-\dfrac{229}3$

Finally,

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3$

5 0

3 years ago

James invested $4,000 at 5% interest per year; how long will it take him to earn $200 in simple interest?

tester [92]

Answer:

It takes 1 year.

Step-by-step explanation:

You have to apply simple interest formula, I = (P×R×T)/100 where I represent interest amount, P is principle, R is interest rate and T is number of years :

$I = \frac{PRT}{100}$