Answer:
6 and 12.
Step-by-step explanation:
Tell "tRiStAn" to build me a treehouse too. Its boring here.
Answer:
Therefore the Area of Rhombus ABCD is 36 unit².
Step-by-step explanation:
Given:
ABCD is a Rhombus
A = (-1,0)
B = (5,-3)
C = (-1,-6)
D = (-7 ,-3)
To Find:
Area of Rhombus ABCD = ?
Solution:
We know that Area of Rhombus is given as

Where ,
d₁ and d₂ are the Diagonals.
We have,
Diagonals as AC and BD,
Using Distance Formula we get

Substituting coordinates A and C we get

Similarly for BD we have,

Now Substituting AC and BD in Formula we get


Therefore the Area of Rhombus ABCD is 36 unit².

Notice that Given that
is an ellipse, consider a conversion to polar coordinates:

The Jacobian for this transformation is

with determinant 
Then the integral in polar coordinates is

where you can evaluate the remaining integral by substituting
and
.
I believe the answer is B! good luck.
Answer:
79.986
Step-by-step explanation:
Let A represent isotope ⁷⁹Br
Let B represent isotope ⁸¹Br
From the question given above, the following data were obtained:
For Isotope A (⁷⁹Br):
Mass of A = 79
Abundance of A (A%) = 50.69%
For isotope B (⁸¹Br):
Mass of B = 81
Abundance of B (B%) = 49.31%
Relative atomic mass of Br =?
The relative atomic mass (RAM) of Br can be obtained as follow:
RAM = [(Mass of A × A%) /100] + [(Mass of B × B%) /100]
= [(79 × 50.69) /100] + [(81 × 49.31) /100]
= 40.0451 + 39.9411
= 79.986 amu
Thus, the relative atomic mass of Br is 79.986