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3 years ago

12

On the first play of a game, a running back gained 7 yards. On the next play, he lost 19 uards. Find the change in yards in thet

two plays

1 answer:

Ivenika [448]3 years ago

6 0

Answer:-12 yards

Step-by-step explanation:7 yards - 19yards

you are at 0 after you subtract 7 and you still need to subtract 12 more and that is how you get -12 subtract 12 frome 0 and you get -12

7-19=-12

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. Use the process outlined in the lesson to approximate the number 3√10. Use the approximation √10 ≈3162 277 7.

GaryK [48]

Answer:

sequence of five intervals

(1) 3³ < $3^{\sqrt{10} }$ < $3^{4}$

(2) $3^{3.1}$ < $3^{\sqrt{10} }$ < $3^{3.2}$

(3) $3^{3.16}$ < $3^{\sqrt{10} }$ < $3^{3.17}$

(4) $3^{3.162}$ < $3^{\sqrt{10} }$ < $3^{3.163}$

(5) $3^{3.1622}$ < $3^{\sqrt{10} }$ < $3^{3.1623}$

Step-by-step explanation:

as per question given data

√10 ≈ 3.162 277 7

to find out

sequence of five intervals

solution

as we have given that √10 value that is here

√10 ≈ 3.162 277 7 ........................1

so

when we find $3^{\sqrt{10} }$ ................2

put here √10 value in equation number 2

we get $3^{\sqrt{10} }$ that is 32.27

so

sequence of five intervals

(1) 3³ < $3^{\sqrt{10} }$ < $3^{4}$

(2) $3^{3.1}$ < $3^{\sqrt{10} }$ < $3^{3.2}$

(3) $3^{3.16}$ < $3^{\sqrt{10} }$ < $3^{3.17}$

(4) $3^{3.162}$ < $3^{\sqrt{10} }$ < $3^{3.163}$

(5) $3^{3.1622}$ < $3^{\sqrt{10} }$ < $3^{3.1623}$

5 0

3 years ago

The length of a string in yards is a function ƒ(n) of the length n in inches. Write a function rule for this situation.

lesya [120]

There are 12 inches in a foot, and 3 feet in a yard, so there are 36 inches in one yard which means that yards = inches/36. So the answer should be:

<span>f(n) = n/36</span>

8 0

3 years ago

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Identify the 25th term of the arithmetic sequence 2, 1 and 3 over 5,

raketka [301]

First, you have to transform your numbers into proper fractions:
1 and 3/5 = (5+3)/5 = 8/5
1 and 1/5 = (5+1)/5 = 6/5

Therefore your arithmetic sequence is 2, 8/5, 6/5, ...

In an arithmetic sequence, the difference between a given term and the preceding one is equal to the difference between the <span>following </span>term and the given one. In your case:
d = 8/5 - 2 = (8-10)/5 = -2/5
As a prove: d = 6/5 - 8/5 = -2/5

Now, in order to find the 25th term you need to apply the formula:
an = a + (n - 1)d
where an is the number you are looking for, a is the first term, n is the term you are looking for and d is the distance.
Hence,
a₂₅ = 2 + (25-1)(-2/5) = 2 - 24·2/5 = 2 - 48/5 = (10-48)/5 = -38/5

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3 years ago

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Plz help me asap !!!

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Answer:

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VladimirAG [237]

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