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steposvetlana [31]
3 years ago
8

A cable company had 260 subscibers.The ratio of regular subscribers to premium subscribers was 10:3.How many regular subscribers

did they have
Mathematics
1 answer:
elena-s [515]3 years ago
4 0
The answer is 200 regular subscribers.

3×20=60 (Premium)
10×20=200 (Regular)
+--------
260 Subscribers

Don't feel afraid to ask more questions I find them fun to answer~!
You might be interested in
What is the answer to -6n^2 - 5n - 7 = -8
soldi70 [24.7K]

Answer:

n = \frac{1}{3} , n = \frac{1}{2}

Step-by-step explanation:

6n² - 5n - 7 = - 8 ( add 8 to both sides )

6n² - 5n + 1 = 0 ← in standard form

Consider the product of the factors of the coefficient of the n² term and the constant term which sum to give the coefficient of the n- term

product = 6 × 1 = 6 and sum = - 5

The factors are - 3 and - 2

Use these factors to split the n- term

6n² - 3n - 2n + 1 = 0 ( factor the first/second and third/fourth terms )

3n(2n - 1) - 1(2n - 1) = 0 ← factor out (2n - 1) from each term

(2n - 1)(3n - 1) = 0 ← in factored form

Equate each factor to zero and solve for n

3n - 1 = 0 ⇒ 3n = 1 ⇒ n = \frac{1}{3}

2n - 1 = 0 ⇒ 2n = 1 ⇒ n = \frac{1}{2}

7 0
3 years ago
Find 6 rational numbers between -2/3 and 1/2?
a_sh-v [17]

Answer:

-3/6 -2/6 -1/6 0/6 1/6 2/6

4 0
3 years ago
35. What percentage is 12 minutes of 4 hours?
Elodia [21]

Answer:

5\%

Step-by-step explanation:

4h = 4  \times 60 \: minutes \\  = 240 \: min \\  \\  \frac{12}{240}  \times 100\% \\  = 5\%

hope this helps you.

Can I have the brainliest please?

have a nice day!

6 0
3 years ago
Read 2 more answers
What is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)?
Rasek [7]

The side lengths of triangle are 6 units, 8 units and 10 units.

<u>SOLUTION: </u>

Given that, we have to find what is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)  

We know that, distance between two points P\left(x_{1}, y_{1}\right) \text { and } Q\left(x_{2}, y_{2}\right) is given by  

P Q=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}

Now,  

\begin{array}{l}{\text { Distance between }(-5,-1) \text { and }(-5,5)=\sqrt{(-5-(-5))^{2}+(5-(-1))^{2}}} \\\\ {\qquad \begin{array}{l}{=\sqrt{(-5-(-5))^{2}+(5-(-1))^{2}}} \\\\ {=\sqrt{(0)^{2}+(5+1)^{2}}=\sqrt{(6)^{2}}=6} \\\\ {=\sqrt{(-5)^{2}+(5+1)^{2}+(5-(-1))^{2}}} \\\\ {=\sqrt{(-8)^{2}+(5+1)^{2}}=\sqrt{64+36}=\sqrt{100}=10} \\\\ {=\sqrt{(3-1)^{2}+(-1-(-1))^{2}}} \\\\ {=\sqrt{(5+3)^{2}+(0)^{2}}=\sqrt{(8)^{2}}=8}\end{array}}\end{array}

8 0
3 years ago
The area of a triangle is 8.50 square inches . The triangles height is 15inches . What is the length of the base?A) 6 inches b)
DochEvi [55]

Answer:

I think you mistyped the question

Step-by-step explanation:

I get 1.13

5 0
3 years ago
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