The mean = 2,000
s = Sigma ( standard deviation ) = 300
M - 2 s = 2,000- 2 * 300 = 2,000 - 600 = 1,400
M + 2 s = 2,000 + 2 * 300 = 2,000 + 600 = 2,600
Answer.
Useful life of light bulbs within 2 standard deviations of the mean is:
A ) Between 1,400 and 2,600 hours
1,000,000 is million
to round look at hundred thousand place or 100,000
see number before million (after comma)
if it is greater than or equal to 5, add 1 to current value of million and say all after is 0
if less than 5 then leave million value as is and make after 0
135,458,267
hundred thousand value is 4
4<5
135,000,000
How do we answer is there’s no pic??
I believe the given limit is
![\displaystyle \lim_{x\to\infty} \bigg(\sqrt[3]{3x^3+3x^2+x-1} - \sqrt[3]{3x^3-x^2+1}\bigg)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Clim_%7Bx%5Cto%5Cinfty%7D%20%5Cbigg%28%5Csqrt%5B3%5D%7B3x%5E3%2B3x%5E2%2Bx-1%7D%20-%20%5Csqrt%5B3%5D%7B3x%5E3-x%5E2%2B1%7D%5Cbigg%29)
Let
Now rewrite the expression as a difference of cubes:
Then
The limit is then equivalent to
From each remaining cube root expression, remove the cubic terms:
Now that we see each term in the denominator has a factor of <em>x</em> ², we can eliminate it :
As <em>x</em> goes to infinity, each of the 1/<em>x</em> ⁿ terms converge to 0, leaving us with the overall limit,
Let x = the length of a side of the square (m).
The area is
A = x²
The perimeter is
P = 4x
The rate of change of P with respect to x is
P'(x) = 4 (independent of x)
When A = 49 m², then x = 7 m.
The rate of P is 4.
Answer: 4
