Actually, this is not about angles. It's about the length of the sides in a right triangle.
In EVERY right triangle, the squares of the lengths of the short sides add up
to the square of the length of the longest side. You're in high school math,so
I'm SURE you've heard that in class before ... possibly even just before you
were assigned this problem.
Let's say that again: The squares of the lengths of the sides that meet at
the right angle add up to the square of the length of the longest side. In
the triangle in this particular problem, that means
a² + b² = c²
You know the lengths of 'b' and 'c', so you shouldn't have any trouble finding
the length of 'a'.
*Hint: When you have two y's, they could equal each other in order to solve for the x value.
|x^2 -3x + 1| = - (x - 1)
x^2 -3x + 1 = -x + 1
x^2 - 2x + 1 = 1
x^2 - 2x = 0
x (x - 2)
x = 2 and x = 0
Once both of them are plugged in, only x = 2 works so that's the value for x. Now we just plug it in order to solve for y.
y = x - 1
y = 2 - 1
y = 1
(2, 1)
The answer would be C.
