I need someones help!

Which statements are true? Select three options. ∠F corresponds to ∠F'. Segment EE' is parallel to segment FF'. The distance fro

Gwar [14]

Answer:

The correct options are (1), (3) and (5).

Step-by-step explanation:

The two triangles are shown below.

The measure of ∠F corresponds to ∠F'.

The distance between the points D and origin is of 9 units.

And the distance between the points D' and origin is 3 units.

Thus, the distance from point D' to the origin is One-third the distance of point D to the origin.

Check for similarity:

$\frac{D'F'}{DF}=\frac{D'E'}{DE}=\frac{F'E'}{FE}=\frac{1}{3}$

Thus, the △DEF is similar to △D'E'F'.

Thus, the correct options are (1), (3) and (5).

4 0

3 years ago

The slope of the line through the points is 2. Which statement describes how the slope relates to the height of the water is the

SOVA2 [1]

Answer:

The height of the water increases 2 inches per minute. Or A

Step-by-step explanation:

Edge

6 0

3 years ago

A government report gives a 99% confidence interval for the proportion of welfare recipients who have been receiving welfare ben

juin [17]

Answer:

The estimation for the proportion for this case is $\hat p = 0.21$

And we know that the 99% confidence interval is given by:

$0.21 \pm 0.045$

So then the margin of error at 99% of confidence is 0.045, and the margin of error is given by this formula:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

If we decrease the confidence level this margin of error can't be higher than 0.045 so then the correct answer for this case would be:

d. 21% ± 4.8%

Because if the z value decrease from 2.58 to 1.96 not makes sense that the margin of error increase from 0.045(4.5%) to 0.048(4.8%)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.