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Tamiku [17]
3 years ago
14

Options: 14 36 16 12

Mathematics
1 answer:
Lerok [7]3 years ago
8 0

Answer:


12 million dollars.


Step-by-step explanation:


Let the sales in the first year be x million .

So the sales in the second year were x + 4 million, in the third year were 3(x + 4) and this is 48 million dollars.

So we have the equation 3(x + 4) = 48

3x + 12 = 48

3x = 36

x = 12 million dollars.

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Leokris [45]
The length of line segment EC is 35
4 0
3 years ago
A website-hosting service charges a one-time setup fee of $20 plus d dollars for each month. A business owner paid $70 for the f
alina1380 [7]

Answer:

D= 10 Dollars each month

Step-by-step explanation:

You find this answer by subtracting the one time fee of 20 from the total payed of 70, leaving you with 50.  You then divide that 50$ by 5 months.

5 0
2 years ago
What is the y-intercept of the line?<br> YA<br> 2<br> -2<br> -2<br> 0
Arturiano [62]

Answer:

1 the line hits the y line at 1

8 0
3 years ago
Please select the best answer from the choices provided
Ira Lisetskai [31]

<u>Answer:</u>

The correct answer option is c. \frac{1}{9a^2}.

<u>Step-by-step explanation:</u>

We are given an expression (27a^{-3})^{-\frac{2}{3} } and we are supposed to simplify it.

We can also write (27a^{-3})^{-\frac{2}{3} } as (\frac{3^3}{a^3} )^{-\frac{2}{3} }.

We know the power rule (a^m)^n=a^{mn} which means that to raise a power to a power you need to multiply the exponents.

So multiplying the exponents to get:

\frac{3^{(3.-\frac{2}{3})} }{a^{(3.\frac{2}{3})} }\\\\\frac{3^{-2}}{a^2}\\ \\\frac{1}{3^2a^2} \\\\\frac{1}{9a^2}

Therefore, the correct answer option is c. \frac{1}{9a^2}.

4 0
3 years ago
Consider randomly selecting a student at a large university. Let A be the event that the selected student has a Visa card, let B
wariber [46]

Answer:

a. 0.76

b. 0.23

c. 0.5

d. p(B/A) is the probability that given that a student has a visa card, they also have a master card

p(A/B) is the probability that given a student has a master card, they also have a visa card

e. 0.35

f. 0.31

Step-by-step explanation:

a. p(AUBUC)= P(A)+P(B)+P(C)-P(AnB)-P(AnC)-P(BnC)+P(AnBnC)

                    =0.6+0.4+0.2-0.3-0.11-0.1+0.07= 0.76

b. P(AnBnC')= P(AnB)-P(AnBnC)

                    =0.3-0.07= 0.23

c. P(B/A)= P(AnB)/P(A)

             =0.3/O.6= 0.5

e. P((AnB)/C))= P((AnB)nC)/P(C)

                     =P(AnBnC)/P(C)

                     =0.07/0.2= 0.35

f. P((AUB)/C)= P((AUB)nC)/P(C)

                    =(P(AnC) U P(BnC))/P(C)

                     =(0.11+0.1)/0.2

                     =0.21/0.2 = 0.31

7 0
2 years ago
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