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Tamiku [17]
3 years ago
14

Options: 14 36 16 12

Mathematics
1 answer:
Lerok [7]3 years ago
8 0

Answer:


12 million dollars.


Step-by-step explanation:


Let the sales in the first year be x million .

So the sales in the second year were x + 4 million, in the third year were 3(x + 4) and this is 48 million dollars.

So we have the equation 3(x + 4) = 48

3x + 12 = 48

3x = 36

x = 12 million dollars.

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nadezda [96]

Answer:

when u distribute a number you are basically giving the number off and multiplying other factors by that number

Step-by-step explanation:

3(x+4) ( distribute the 3 ) so u would multiply the 3 by both factors ( the x and the 4) getting 3x+12

7 0
3 years ago
What is the slope of the line through (-4,2) and (3, 3)? "/ yo Choose 1 answer: 19 21 42 142 A А 7 5 B 7 5 5 7 5 7 e slope an​
NNADVOKAT [17]

Answer:

1/7

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(3-2)/(3-(-4))

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5 0
3 years ago
Zachery is solving the equation 3/4 (x - 8) = 12
Maru [420]

Answer:

3/4*x - 3/4*8=12

3/4x -6=12

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Step-by-step explanation:

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6 0
2 years ago
Suppose the half-life of a material is 10 days. You have one 1 kg of the material today. How much of the material would you have
boyakko [2]

Answer:

0.50 kg of the material would be left after 10 days.

0.25 kg of the material would be left after 20 days.

Step-by-step explanation:

We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after  10 days and 20 days, respectively.

We will use half life formula.

A=a\cdot(\frac{1}{2})^{\frac{t}{h}}, where,

A = Amount left after t units of time,

a = Initial amount,

t = Time,

h = Half-life.

A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{10}{10}}

A=1\text{ kg}\cdot(\frac{1}{2})^{1}

A=1\text{ kg}\cdot\frac{1}{2}

A=0.5\text{ kg}

Therefore, amount of the material left after 10 days would be 0.5 kg.

A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{20}{10}}

A=1\text{ kg}\cdot(\frac{1}{2})^{2}

A=1\text{ kg}\cdot\frac{1^2}{2^2}

A=1\text{ kg}\cdot\frac{1}{4}

A=0.25\text{ kg}

Therefore, amount of the material left after 20 days would be 0.25 kg.

6 0
3 years ago
Picture attached, please simplify
Charra [1.4K]
The answer is the second option given
6 0
2 years ago
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