Protons Ha and Hb in the compound given are enantiotopic.
<h3>What are enantiotopic protons?</h3>
Enantiotopic protons can be defined as those protons that can be replaced by another groups like deuterium.
<h3>What is a compound?</h3>
A compound is a substance which contains two or more elements chemically combined together.
So therefore, Protons Ha and Hb in the compound given are enantiotopic.
Learn more about enantiotopic protons:
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the answer is false at lest that is what i know
Answer:
The electronic configuration that are incorrectly written is 1s²2s³2p⁶, 4s²3d¹⁰4p⁷, 3s¹ and 2s²2p⁴.
Explanation:
The electronic configuration of the elements corresponds to how all the electrons of an element are arranged in energy levels and sub-levels.
There are 7 energy levels —from 1 to 7— whose sublevels are described as s, p, d and f.
All electronic configurations begin with the term "1s" —corresponding to the sublevel s of level 1— so 4s²3d¹⁰4p⁷, 3s¹ and 2s²2p⁴ are incorrectly written. In addition, 4s²3d¹⁰4p⁷ is written incorrectly because is impossible to jump from the sublevel "s" to the sublevel "d" —which is found from level 3 and up— without passing through the sublevel "p".
In the case of 1s²2s³2p⁶, the wrong thing is that the sublevel "s" can only hold two electrons, not three.
The other options are correctly written.
I believe the answer is B??????????? Hope this helps
~Queensupreme
