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Oliga [24]
3 years ago
6

Calculate the ph of a solution in which [oh−]=7.1×10−3m.express the ph of the solution to two decimal places.

Chemistry
1 answer:
Phoenix [80]3 years ago
6 0

Answer is: pH value of solution is 11.85.<span>
[</span>OH⁻] = 7.1·10⁻³ M;  equilibrium concentration of hydroxide anions.

[OH⁻]·[H⁺] = Kw.

0.0071 mol/L · [H⁺] = 10⁻¹⁴ mol²/L².

[H⁺] = 10⁻¹⁴ mol²/L² ÷ 7.1·10⁻³ mol/L.

[H⁺] = 1.4·10⁻¹² mol/L.

pH = -log[H⁺].

pH = -log(1.4·10⁻¹² mol/L).

pH = 11.85.

If pH is less than seven, solution is acidic; greater than seven, solution is basic; equal seven, solution is neutral.

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How many elements are in Li2SO4?how many elements are in li2s 04 how many elements are in li2s 04 ​
Free_Kalibri [48]

Answer:

3

Explanation:

the three elements involved in this compound are Li, S, O.

lithium, sulfur, and oxygen. Which create the ionic compound, "Lithium Sulfate."

7 atoms total, since there are two lithium, four oxygen, and one sulfate atom. this is a white inorganic salt.

6 0
3 years ago
Please Help! It says fill in the blanks to complete the Punnett square below to show the results of a cross between a homozygous
makkiz [27]

Answer:

Genotypes: Homozygous (GG)=50%, Heterozygous (Gg)=50%.

Phenotypes: Homozygous gray (GG)=50%, Heterozygous gray (Gg)=50% or just Gray=100%

Explanation:

Hello,

The Punnett square for this cross turns into:

\left[\begin{array}{ccc}&G&g\\G&GG&Gg\\G&GG&Gg\end{array}\right]

It means that the genotypes and phenotypes are:

Genotypes: Homozygous (GG)=50%, Heterozygous (Gg)=50%.

Phenotypes: Homozygous gray (GG)=50%, Heterozygous gray (Gg)=50% or just Gray=100%

Best regards.

4 0
3 years ago
Critical Thinking Challenge: A student has a part time
mina [271]

Answer:

6⅔ shifts

Explanation:

From the question given:

A shift = 4 hours

Pay = $8.25 per hour

Next, we shall determine the number of hours that will result in a pay of $220. This can be obtained as follow:

$8.25 = 1 hour

Therefore,

$220 = $220 × 1 hour / $8.25

$220 = 220/8.25 hours.

$220 = 80/3 hours

$220 = 26⅔ hours

Therefore, it will take 26⅔ hours to receive a pay of $220.

Finally, we shall determine the number of shifts in 26⅔ hours. This can be obtained as follow:

4 hours = 1 shift

Therefore,

26⅔ hours = 26⅔ ÷ 4

26⅔ hours = 80/3 × 1/4

26⅔ hours = 80/12

26⅔ hours = 20/3

26⅔ hours = 6⅔ shifts

Therefore, she will work 6⅔ shifts in order to receive a pay of $220

6 0
3 years ago
Name the following structure
Paraphin [41]

Answer:

2–butyne.

Explanation:

To name the compound given above, we must determine the following:

1. Determine the functional group of the compound.

2. Determine the longest continuous carbon chain. This gives the parent name of the compound.

3. Locate the position of the functional group by giving it the lowest possible count.

4. Combine the above to obtain the name.

Thus, we shall name the compound as follow:

1. The compound contains triple bond (C≡C). Therefore, the compound is an alkyne.

2. The longest chain is carbon 4. Thus the parent is butyne.

3. The triple bond (C≡C) is located at carbon 2 when we count from either side.

4. The name of the compound is:

2–butyne

4 0
2 years ago
Name a possible product of this reaction in the presence of ether and AlCl3: methylbenzene + 1-chlorodecane.a. 1-methyl-2-decylb
Vikki [24]

Answer:

None of these

Explanation:

Friedel–Craft reaction is a reaction involves the attachment of substituents to the benzene ring.

Mechanism of the reaction of methylbenzene with 1-chlorodecane in the presence of ether and aluminum chloride :

Step -1 : Generation of stable carbocation.

Aluminium chloride acts as Lewis acid which removes the chloride ion from the alkyl halide forming carbocation. The primary carbocation thus formed gets rearranged to secondary primary carbocation which is more stable due to hyperconjugation.

Step-2: Attack of the ring to the carbocation

The pi electrons of the ring behave as a nucleophile and attacks the carbocation. Since, the group attached on the benzene is methyl (+R effect) , the attack is from the ortho and the para positions. Para product is more stable due to less steric hinderance.

The product formed is shown in mechanism does not mention in any of the options.

So, None of these is the answer

8 0
3 years ago
Read 2 more answers
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