Answer:
Only reaction 1
Explanation:
C + O2 → CO
the charge of C in CO is +2 (oxidation)
from 0 to +2
the charge of O in CO is -2 (reduction)
from 0 fo -2
Hence it is a redox (reduction-oxidation) reaction
This is also valid for,
C + O2 → CO2
the charge of C in CO2 is +4 (oxidation)
charge increases from 0 to +4
the charge of O in CO2 is -2 (reduction)
charge decreases from 0 to -2
hence, it is a redox reaction
K2SO4 + CaCl → KCl + CaSO4
none of the charges changes in this reaction
please recheck, for this may not be the correct answer
Is this a chemistry pun? It's <span>carbon.</span>
What does it happen in smallest scale?
<span>You have to look for "DUPRE' EQUATION" which treat about </span>
<span>"TWO-PHASE INTERFACIAL FORCEs". </span>
<span>At boundary surface between two aggregation phases, you may attribute upper energy level to molecules standing at the boundary zone. So, it has to define INTERFACIAL FORCEs WHICH ACT TO REMODEL SHAPE AND EXTENSION OF MEETING PHASEs. </span>
<span>In your case, Water's Droplet is a liquid phase surrounded by Air (e.g. gas phase) and Interfacial Forces act to dominate Boundary-Surface. </span>
<span>Mathematically, smallest possible Surface comes to SPHERICAL SHAPE. </span>
Answer:
C + 2H2 ⇒ CH4
Explanation:
In order to balance a chemical equation you need to make sure that the number of atoms on both sides are equal
C + H2 = CH4
C = 1
H = 2
Products:
C = 1
H = 4
H2 = 2 × 2 = 4
C + 2H2 ⇒ CH4
Hope this helps.
Answer:
- <em>If the volume is doubled and the pressure is tripled, </em><em><u>the temperature changes by a factor of 6.</u></em>
Explanation:
Since, for ideal gases the temperature is in direct relation to the volume and the pressure, you can predict that if the volume is doubled and the pressure is tripled the effect on the temperature will be 3 × 2 = 6 times.
You can prove it using the combined law of gases:
Where the letters P denote absolute pressures, the letters T denote temperature measured in absolute scale, and the letters V denote volume.
The changes given may be written it this way:
Then, you can write T₂ in terms of the other variables:
- T₂ = (P₂ V₂ T₂) / (P₁ V₁) = 3P₁ 2V₁ T₂ / (P₁V₁)
Cancel the common factors P₁ and V₁
Which proves that the final temperature is 6 times the initial temperature.