Use the following equations to fill the chart.
E = hf
where
h = 6.63 x 10⁻³⁴ J/s, Planck's constant
f = frequency Hz
E = quanta of energy, J
c = fλ
where
c = 3 x 10⁸ m/s, the velocity of light
λ = wavelength, m
If energy is given in J/mmol, divide by Avogadro's number, N = 6.02 x 10²³, to convert it to J.
The completed table is shown below.
The answer is 2................ :)
Answer:
Li atoms readily give up one electron to form positively charged, Li+ ions. These ions have the same stable electron configuration as the noble gas helium. All Group 1 atoms can lose one electron to form positively charged ions.
Explanation:
Add up the molar mass of Mercury Oxide, and then divide the molar mass of Oxygen by the molar mass of the compound.
So...
mm of Hg + mm of O= 200.59g + 16g= 217g
16g/217g = .0737... x 100 = 7.37%