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Virty [35]
3 years ago
14

What is the concentration of your solution?

Chemistry
1 answer:
Nataliya [291]3 years ago
3 0

Answer:

The volume of unknown sample would be 2.5 mL.

Explanation:

Given data:

Molarity of unknown sample=M₁= 1 M

Molarity of sulfuric acid = M₂= 0.100 M

Volume of sulfuric acid = V₂= 25 mL

Volume of unknown sample=V₁  = ?

Solution:

Formula:

M₁V₁   =  M₂V₂

Now we will put the values in formula:

1M × V₁   =  0.100 M × 25 mL

V₁   =  0.100 M × 25 mL / 1 M

V₁   = 2.5 mL

The volume of unknown sample would be 2.5 mL.

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aleksandr82 [10.1K]

Answer:

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3 0
3 years ago
Iodine-138 decays by beta decay. What element does it produce?
iVinArrow [24]

{xe}^{138}

Explanation:

the bottom number would be 54. This is because you add one to 53 to make it 54 and you add 0 to 138.

4 0
2 years ago
Read 2 more answers
If 650. grams of C6H12O6 (FW 180.16) reacts with 650. grams of O2 (FW 32.00) in cellular respiration: C6H12O6 6 O2 --> 6 CO2
cestrela7 [59]

Answer:

O2 is limiting reactant

Explanation:

To find the limiting reactant we need to convert the mass of each reactant to the moles using the formula weight. And, as 1 mole of C6H12O6 reacts with 6 moles of O2, we can know wich reactant will be over first (Limiting reactant) as follows:

<em>Moles C6H12O6:</em>

650g * (1mol/180.16g) = 3.608 moles C6H12O6

<em>Moles O2:</em>

650g * (1mol/32g) = 20.31 moles O2

Now, for a complete reaction of 3.608 moles of C6H12O6 are required:

3.608 moles C6H12O6 * (6mol O2 / 1mol C6H12O6) = 21.65 moles O2

As there are just 20.31 moles of O2,

<h3>O2 is limiting reactant</h3>
4 0
2 years ago
How many kg are in 50 lb luggage bag
Darya [45]
There are 0.454 kg in 1 lb

Cross multiply

0.454 kg = 1 lb
X kg. = 50 lb

50* 0.454 = 22.7 kg

Answer : 22.7 kg in 50 lbs
7 0
3 years ago
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A chemical reaction produces 653 550 kj of energy as heat in 142.3min. calculate the rate of energy transferred in kj per minute
miskamm [114]

We have the value of  

Total energy produced in the chemical reaction=653 550 KJ  

Time needed=142.3min  

To calculate the rate of energy transfer, that is the amount of energy produced per minute.  

Rate of energy transfer=\frac{Total energy produced}{Time needed}

=\frac{653 550}{142.3}

=4592.76 KJ min⁻¹

So, the rate of energy transfer is 4592.76 KJ min⁻¹.

6 0
3 years ago
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