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Dahasolnce [82]
3 years ago
13

The sum of three guys ages is 62. Angelo is two years younger than Aaron and Alfred is four years older than twice Aaron's age.

What are the ages of each guy?
Mathematics
1 answer:
marishachu [46]3 years ago
6 0

Answer: Angelo is 13 years old.

Aaron is 15 years old

Alfred is 34 years old

Step-by-step explanation:

Let x represent the age of Angelo.

Let y represent the age of Aaron.

Let z represent the age of Alfred

The sum of three guys ages is 62. It means that

x + y + z = 62 - - - - - - - - - - -1

Angelo is two years younger than Aaron. It means that

x = y - 2

Alfred is four years older than twice Aaron's age. It means that

z = 2y + 4

Substituting x = y - 2 and z = 2y + 4 into equation 1, it becomes

y - 2 + y + 2y + 4 = 62

4y + 2 = 62

4y = 62 - 2 = 60

y = 60/4 = 15

x = y - 2 = 15 - 2

x = 13

z = 2y + 4 = 2 × 15 + 4

z = 34

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4 years ago
2. Ravi purchased an old house for Rs. 76.5000 and
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Answer:

Rs. 924000.

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4 years ago
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a farmer wants to fence in a rectangular plot of land adjacent to the north wall of his barn. no fencing is needed along the bar
xenn [34]

The constraint for the maximum enclosed area is the amount the farmer is

willing to spend on fencing.

The width of the plot that will give the most area, y = <u>83.</u>\underline{\overline 3}<u> feet</u>

The length of the plot that will give the most area, y = <u>125 feet</u>

Reasons:

The given parameters are;

The cost of fencing per foot = $20

The maximum amount the farmer is willing to spend = $5000

Number of sides of fencing = 3 sides

Cost of the west side of the = Split with neighbor

Solution:

Let, y, represent the length of the fence, and let <em>x</em> represent the width of

the fence, we have;

Length of fence required = y + 2·x

Cost of the fence = 20·y + 20·x + (20÷2)·x = 20·y + 30·x

Therefore;

Maximum amount to be spent on the fence, 5000 = 20·y + 30·x

\therefore y = \dfrac{5000 - 30 \cdot x}{20}  = 250 - \dfrac{3}{2} \cdot x

y =  \mathbf{250 - \dfrac{3}{2} \cdot x}

Area of a rectangle = Length × Width

The enclosed rectangular area of the fencing, A = y × x

\therefore A = \left(250 - \dfrac{3}{2} \cdot x\right) \cdot x = 250 \cdot x - \dfrac{3}{2} \cdot x^2

\therefore A  =  -\mathbf{ \dfrac{3}{2} \cdot x^2 + 250 \cdot x}

The leading coefficient of the quadratic function of the area is negative,

therefore, the function only has a maximum point.

At the point of the most area, the slope, \dfrac{dA}{dx} = 0

Finding the value of <em>x</em> at the maximum point, we get;

\dfrac{dA}{dx} = \mathbf{ \dfrac{d}{dx} \left( 250 \cdot x - \dfrac{3}{2} \cdot x^2\right)} = 250- 3 \cdot x = 0

Therefore;

\mathrm{ The \ width \ of \ the \ plot \ that \ will \ enclose \ the \ area}, \ x = \dfrac{250}{3} \ feet = \underline{83.\overline 3 \ feet}

\mathrm{ The \ length \ of \ the \ plot \ that \ will \ enclose \ the \ area}, \ y =  250 - \dfrac{3}{2} \times  \dfrac{250}{3} = 125

The length of the plot that will give the most area, y = <u>125 feet</u>

Learn more here:

brainly.com/question/16337916

brainly.com/question/16545343

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