Sum/difference:
Let

This means that

Now, assume that
is rational. The sum/difference of two rational numbers is still rational (so 5-x is rational), and the division by 3 doesn't change this. So, you have that the square root of 8 equals a rational number, which is false. The mistake must have been supposing that
was rational, which proves that the sum/difference of the two given terms was irrational
Multiplication/division:
The logic is actually the same: if we multiply the two terms we get

if again we assume x to be rational, we have

But if x is rational, so is -x/15, and again we come to a contradiction: we have the square root of 8 on one side, which is irrational, and -x/15 on the other, which is rational. So, again, x must have been irrational. You can prove the same claim for the division in a totally similar fashion.
Answer:
5b + 12c
Step-by-step explanation:
-5a +5 a = 0
12b-7b = 5b
12c= 12c
therefore you have the expression 5b+12c
Answer:
(4, 7)
Step-by-step explanation:
The point of interest is ...
P = (2Z +1Y)/(2+1) = ((2·3+6)/3, (2·9+3)/3)
P = (4, 7)
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The point that divides the segment into the ratio a:b is the weighted average of the endpoints, with the weights being "b" and "a". The weight of the first end point corresponds to the length of the far end of the segment.
Answer:
b: 4
Step-by-step explanation:
i took the test on edge 2020