Numbers that come one after the other are called consecutive numbers.

Mathematics

1 answer:

KonstantinChe [14]3 years ago

3 0

Answer:

Step-by-step explanation:

Here, we want to get the number that will be in the units place

Six consecutive numbers from 33 are;

33 , 34 , 35 , 36 , 37 , 38 ,

Product of 5 and any of the even numbers will yield 0

That means the number on the unit place is 0

You might be interested in

PLEASE HELP FOR 87 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!

Anton [14]

1. You can expand the coefficients to yield 6, and add the powers since the bases are the same (ie A)

2. y⁻² can also be rewritten as 1/y², so it becomes 1/y² · 1/y⁵ = 1/y⁷ (ie C)

3. Only the x is affected by the power.

4. y = 3·5ˣ doesn't change in slope, so it essentially is similar to a 5ˣ graph.

5. Should be pretty straight forward.
6. Should be pretty straight forward.
7. Should be pretty straight forward.

8. Since x is the length of the border, calculate the area of the frame and subtract that from the area of the square painting. (Remember that the length of the square painting is x - 8, not x - 4)

9. Should be pretty straight forward.
11 - 25 are pretty much similar to each other.
If you have trouble, let me know and I'll walk you through it.

6 0

3 years ago

Read 2 more answers

You have been assigned to determine whether more people prefer Coke or Pepsi. Assume that roughly half the population prefers Co

Alex Ar [27]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11$

And rounded up we have that n=1068

Step-by-step explanation:

For this case we have the following info given:

$ME=0.03$ the margin of error desired

$Conf= 0.95$ the level of confidence given

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

the critical value for 95% of confidence is $z=1.96$

We can use as estimator for the population of interest $\hat p=0.5$ . And on this case we have that $ME =\pm 0.03$ and we are interested in order to find the value of n, if we solve n from equation (a) we got: