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GaryK [48]
3 years ago
7

3. There are 124 acorns laying on the ground in your yard, it is predicted that the number of acorns will

Mathematics
1 answer:
Gennadij [26K]3 years ago
5 0

Answer:

507,409

Step-by-step explanation:

if every 5 days the number quadruples (x4), and we want to know how many acorns fall after 30 days, we can divide 30 by 5 so we only have to calculate for the amount of time the take to quadruple.

30 ÷ 5 = 6

so we only have to quadruple the acorns 6 times.

if we start off with 124 acorns, this is what it will look like:

Day 0: 124 acorns

Day 5: 124 x 4 = 496 acorns

Day 10: 496 x 4 = 1984 acorns

Day 15: 1984 x 4 = 7936 acorns

etc... until day 30.

Day 30: 507904 acorns

I hope this was helpful :-)

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If A= [2 6] prove that (A')' = A<br> 3 7<br> 4 9​
Ivanshal [37]

Answer:if A= [2 6] prove that (A')' = A

3 7

4 9​

Step-by-step explanation:

3 0
1 year ago
Values for relation g are given in the table. Which ordered pair would be found in the inverse of g? X Y 2 2 3 5 4 9 5 13 A: (4,
Bumek [7]

Answer:

D (13,5)

Step-by-step explanation:

X 2 3 4 5

Y 2 5 9 13

So the ordered pairs are (2,2),(3,5), (4,9), (5,13)

and the ordered pairs for the inverse are

(2,2),(5,3), (9,4), (13,5)

from which D (13,5) is found among the options.

5 0
3 years ago
WILL MARK BRAINLEST IF CORRECT HELP ME OUT
sveta [45]

Answer:

x = 12

Step-by-step explanation:

Equation:    0.52(x) + 0.72(4) = 0.57(x + 4)

0.52(x) + 0.72(4) = 0.57(x + 4)             \longmapsto         Multiply

0.52x + 2.88 = 0.57x + 2.28               \longmapsto         Subtract 0.52x from both sides

2.88 = 0.05x + 2.28                            \longmapsto         Subtract 2.28 from both sides

0.6 = 0.05x                                          \longmapsto        Divide all sides by 0.05

 

x = 12

-Chetan K

6 0
2 years ago
Wats da anwser 4×70=4×7×_
Veseljchak [2.6K]
10 will be your answer
6 0
3 years ago
Read 2 more answers
I need help please it’s really hard and I don’t understand it
mr_godi [17]

The line segment HI has length 3<em>x</em> - 5, and IJ has length <em>x</em> - 1.

We're told that HJ has length 7<em>x</em> - 27.

The segment HJ is made up by connecting the segments HI and IJ, so the length of HJ is equal to the sum of the lengths of HI and IJ.

This means we have

7<em>x</em> - 27 = (3<em>x</em> - 5) + (<em>x</em> - 1)

Solve for <em>x</em> :

7<em>x</em> - 27 = (3<em>x</em> + <em>x</em>) + (-5 - 1)

7<em>x</em> - 27 = 4<em>x</em> - 6

7<em>x</em> - 4<em>x</em> = 27 - 6

3<em>x</em> = 21

<em>x</em> = 21/3

<em>x</em> = 7

5 0
3 years ago
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