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slava [35]
3 years ago
8

A quality control technican checked a sample of 30 bulbs. Two of the bulbs were defective. If the sample was representative, fin

d the number of bulbs expected to be defective in a case of 450.
Mathematics
1 answer:
masha68 [24]3 years ago
3 0

Answer:30

Step-by-step explanation: Put 30 times 15 into a calulater. Then do 15 times  2 then you find your answer.

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Find the volume of a sphere
lukranit [14]

v=4/3 πr^3.

Use this formula

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A direct variation function includes the ordered pair (4, 5). Which statement is true? The constant of variation k is mc001-1.jp
devlian [24]
A direct variation suggest that the value of x in the equation would greatly affect the value of y such that when x is increasing, y also increases and the other way around. The equation for a direct variation is that,
                               y  = kx
Substituting the given values in the ordered pair,
                           5 = k(4)   ; k = 5/4
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PLEASE HELP ME ANSWER ASAP!
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Either twice or more than twice. But I’d go with twice
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find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B
SashulF [63]

Answer:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3

|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{ab}{|a| |b|}

And the angle is given by:

\theta = cos^{-1} (\frac{ab}{|a| |b|})

If we replace we got:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

3 0
2 years ago
Question 1(Multiple Choice Worth 5 points)
ioda
15/31 is the answer
7 0
2 years ago
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