Answer:
18/42
Step-by-step explanation:
Find the common factor of the denominators i.e the common factor of 7 and 42. The answer is 6. Multiply the fraction with the smallest denominator by the common factor (3/7 ×6/6) answer is 18/42
Hope you understand
<h3>
Answer: 24 yards, choice D</h3>
There are 4 sides to this figure (trapezoid). The left slanted side and the right most vertical side, combined with the top and bottom horizontal sides, will get us the perimeter.
left slanted side = 5 yards
right most vertical side = 4 yards (see note below)
bottom side = 9 yards
top side = 6 yards
Add up the four sides mentioned: 5+4+9+6 = 9+15 = 24
note: the rectangle has opposite sides that are the same length. While the right most side isn't labeled, it is the same length as the left side of the rectangle, so both are 4 yards long.
Another thing I should probably mention is that we do not add in the interior 4 yard side. The perimeter is only the outer or exterior sides we care about. Think of it like we're trying to fence around some property lot and we don't want to subdivide the property up. Finding the perimeter will help us find the amount of fencing needed to surround the property.
< P is a right angle.....a right angle is 90 degrees.
< P and < Q form a linear pair....a linear pair, when added, = 180 degrees
so if < P is 90.....and when added to < Q = 180...
90 + Q = 180
Q = 180 - 90
Q = 90 <== so < Q is also a right angle...measures 90 degrees
Let us formulate the independent equation that represents the problem. We let x be the cost for adult tickets and y be the cost for children tickets. All of the sales should equal to $20. Since each adult costs $4 and each child costs $2, the equation should be
4x + 2y = 20
There are two unknown but only one independent equation. We cannot solve an exact solution for this. One way to solve this is to state all the possibilities. Let's start by assigning values of x. The least value of x possible is 0. This is when no adults but only children bought the tickets.
When x=0,
4(0) + 2y = 20
y = 10
When x=1,
4(1) + 2y = 20
y = 8
When x=2,
4(2) + 2y = 20
y = 6
When x=3,
4(3) + 2y= 20
y = 4
When x = 4,
4(4) + 2y = 20
y = 2
When x = 5,
4(5) + 2y = 20
y = 0
When x = 6,
4(6) + 2y = 20
y = -2
A negative value for y is impossible. Therefore, the list of possible combination ends at x =5. To summarize, the combinations of adults and children tickets sold is tabulated below:
Number of adult tickets Number of children tickets
0 10
1 8
2 6
3 4
4 2
5 0
