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lozanna [386]
3 years ago
10

Drag each tile to the correct box

Mathematics
1 answer:
Bezzdna [24]3 years ago
8 0

Answer:

Add fifteen to both sides

90/6=15

1st one is 15

26 + 10= 36

36/2=18

18 + (18-10=8) 18 + 8 = 26

The second is 18

Subtract the 5-3=2 so 10/2=5

5 x 5 = 25 - 5 x 3 = 15

25 - 15 = 10

5 is the third answer

2 x 12 = 24 - 1 = 23 x 2 = 46 so the last one is 12

In order the answers are 15,18,5 and 12.

Step-by-step explanation:

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Write a function describing the relationship of the given variables.
zhuklara [117]

Answer:

The function is A = 10√r

Step-by-step explanation:

* Lets explain the meaning of direct variation

- The direct variation is a mathematical relationship between two

  variables that can be expressed by an equation in which one

  variable is equal to a constant times the other

- If Y is in direct variation with x (y ∝ x), then y = kx, where k is the

 constant of variation

* Now lets solve the problem

# A is varies directly with the square root of r

- Change the statement above to a mathematical relation

∴ A ∝ √r

- Chang the relation to a function by using a constant k

∴ A = k√r

- To find the value of the constant of variation k substitute A and r

 by the given values

∵ r = 16 when A = 40

∵ A = k√r

∴ 40 = k√16 ⇒ simplify the square root

∴ 40 = 4k ⇒ divide both sides by 4 to find the value of k

∴ 10 = k

- The value of the constant of variation is 10

∴ The function describing the relationship of A and r is A = 10√r

8 0
3 years ago
Read 2 more answers
PLEASE HELP ILL MARK BRAINLY!!!!!!!!
BaLLatris [955]

Answer:

2

Step-by-step explanation:

7 0
3 years ago
Solve -2/3 and x- intercept 5
lions [1.4K]

Answer:

y= -2/3x+10

Step-by-step explanation:

-2/3=slope, x-intercept=5 = (5,0)

formula is y-y1=m(x-x1)

(5,0) ---> 5=x1 0=y1

y-0= -2/3(x-5)

y-0= -2/3x+10

+0           +0

y= -2/3x+10

7 0
3 years ago
Need some help with this question in the image ​
Leya [2.2K]

Answer:

1a. first 7×9=63 Then substracting 16 we get 47 and 2-47= -45

3 0
2 years ago
Read 2 more answers
3. The math department needs to buy new textbooks and laptops for their
Alenkasestr [34]

Let they be x.

Cost of textbooks + laptops cant greater than total amount.

(cost of 1 textbooks * number of textbooks) + (cost of 1 laptop * number of laptops ≤ 6500

(30*116) + (x*439) ≤ 6500

3480 + 439x ≤ 6500

439x ≤ 3020

x ≤ 6.8(approx)

Last natural number is 6, says, they can buy 6 laptops at max.

3 0
3 years ago
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