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ankoles [38]
3 years ago
13

The first task you are assigned in your summer laboratory job is to prepare a concentrated naoh stock solution. the molecular we

ight of naoh is 40. how many grams of solid naoh will you need to weigh out to obtain a 750 ml solution that has a concentration of 8 m?
Chemistry
1 answer:
tensa zangetsu [6.8K]3 years ago
7 0

240 g NaOH

<em>Step 1</em>. Calculate the moles of NaOH

Moles of NaOH = 0.750 L solution × (8 mol NaOH/1 L solution) = 6 mol NaOH

Step 2. Calculate the mass of NaOH

Mass of NaOH = 6 mol NaOH × (40 g NaOH/1 mol NaOH) = 240 g NaOH

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Murrr4er [49]

Answer:

Look at the properties of Oxygen and Silicon - the two most abundant elements in the Earth's crust - by clicking on their symbols on the Periodic Table.

Explanation:

7 0
3 years ago
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What is the charge on an ion that has an atomic number of 16 and contains 14e-?
lora16 [44]
The answer would be 2+ since the atomic number represents how many protons are in the element. In this case, there are 16 protons, but only 14 electrons, which means there are an additional 2 protons, hence the 2+ charge on the ion.
3 0
2 years ago
Sodium (Na) and potassium (K) are in the same group in the periodic table. Sodium is in the 11th position. How many valence elec
lapo4ka [179]
It's 1 because there is only one electron on the outer shell.
8 0
3 years ago
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3.2 moles of H3PO4 to grams
Nimfa-mama [501]

Answer:

313, 6grams of H3PO4

Explanation:

We calculate the weight of 1 mol of H3PO4:

Weight 1 mol H3PO4= (Weight H)x3+ (Weight P)+(Weight 0)x4  =1gx3+31g+16gx4

Weight 1 mol H3PO4=98 g /mol

1 mol-----98 grams H3PO4

3,2mol----x= (3,2molx 98 grams H3PO4)/ 1mol=313,6 grams H3PO4

4 0
3 years ago
What is the molarity of a solution in which 7.1 g of sodium sulfate is dissolved in enough water to make 100. mL of solution?
Sidana [21]

Answer:

0.50 M

Explanation:

Given data

  • Mass of sodium sulfate (solute): 7.1 g
  • Volume of solution: 100 mL

Step 1: Calculate the moles of the solute

The molar mass of sodium sulfate is 142.04 g/mol. The moles corresponding to 7.1 grams of sodium sulfate are:

7.1g \times \frac{1mol}{142.02g} = 0.050mol

Step 2: Convert the volume of solution to liters

We will use the relation 1 L = 1000 mL.

100mL \times \frac{1L}{1000mL} =0.100L

Step 3: Calculate the molarity of the solution

M = \frac{moles\ of\ solute }{liters\ of\ solution} = \frac{0.050mol}{0.100L} =0.50 M

3 0
3 years ago
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