Taking into accoun the STP conditions and the ideal gas law, the correct answer is option e. 63 grams of O₂ are present in 44.1 L of O2 at STP.
First of all, the STP conditions refer to the standard temperature and pressure, where the values used are: pressure at 1 atmosphere and temperature at 0°C. These values are reference values for gases.
On the other side, the pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:
P×V = n×R×T
where:
- P is the gas pressure.
- V is the volume that occupies.
- T is its temperature.
- R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances.
- n is the number of moles of the gas.
Then, in this case:
- P= 1 atm
- V= 44.1 L
- n= ?
- R= 0.082
- T= 0°C =273 K
Replacing in the expression for the ideal gas law:
1 atm× 44.1 L= n× 0.082 × 273 K
Solving:
n=1.97 moles
Being the molar mass of O₂, that is, the mass of one mole of the compound, 32 g/mole, the amount of mass that 1.97 moles contains can be calculated as:
= 63.04 g ≈ <u><em>63 g</em></u>
Finally, the correct answer is option e. 63 grams of O₂ are present in 44.1 L of O2 at STP.
Learn more about the ideal gas law:
I'm pretty sure the answer is B double check to make sure it isn't A
Answer:
- An ion is a charged particle.
- Ion may consist of a single charged atom or a group of atoms that have a net charge on them.
- A negatively charged ion is called anion.
- A positively charged ion is called cation.
<h3>For Example,</h3>
Sodium: Na⁺, Chloride: Cl⁻, Ammonium: NH₄⁺ Carbonate: CO₃²⁻
<u>-TheUnknownScientist</u><u> 72</u>
The question is missing a part, so the complete question is as follows:
The protein catalase catalyzes the reaction The Malcolm Bladrigde National Quality Awards aims to: 2H2O2 (aq) ⟶ 2H2O (l) + O2 (g) and has a Michaelis-Menten constant of KM = 25mM and a turnover number of 4.0 × 10 7 s -1. The total enzyme concentration is 0.012 μM and the intial substrate concentration is 5.14 μM. Catalase has a single active site. Calculate the value of Rmax (often written as Vmax) for this enzyme. Calculate the initial rate, R (often written as V0), of this reaction.
1) Calculate Rmax
The turnover number (Kcat) is a ratio of how many molecules of substrate can be converted into product per catalytic site of a given concentration of enzyme per unit of time:
Kcat = 
,
where:
Vmax is maximum rate of reaction when all the enzyme sites are saturated with substrate
Et is total enzyme concentration or concentration of total enzyme catalytic sites.
Calculating:
Kcat =
Vmax = Kcat · Et
Vmax = 4×
· 1.2 × 
Vmax = 4.8 × 
M
2) Calculate the initial rate of this reaction (R):
The Michaelis-Menten equation studies the dynamics of an enzymatic reaction. This model can explain how an enzyme enhances the rate of a reaction and how the reaction rate depends on the concentration of the enzyme and its substrate. The equation is:
V0 = ![\frac{[S].(Vmax)}{KM + [S]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BS%5D.%28Vmax%29%7D%7BKM%20%2B%20%5BS%5D%7D)
, where:
[S] is the substrate's concentration
KM is the Michaelis-Menten constant
Substituting [S] = 5.14 × 
, KM = 2.5 × 
and Vmax = 4.8 × , the result is V0 = 0.478 M.
The answers are Vmax = 4.8 × M and V0 = 0.478 M.
A meander, in general, is a bend in a sinuous watercourse or river. A meander forms when moving water in a stream erodes the outer banks and widens its valley, and the inner part of the river has less energy and deposits silt.
