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Sergeu [11.5K]
3 years ago
11

A science lab has several beakers containing different amounts of the same liquid, as shown in the line plot. If all the liquid

from the beakers is poured into one empty container that can hold exactly 4 liters, how much more liquid can the container hold? liter(s)
Mathematics
2 answers:
denis23 [38]3 years ago
6 0

Answer:

1/5 liters

Step-by-step explanation:

yulyashka [42]3 years ago
4 0

Answer:

1/2

Step-by-step explanation:

There are 7 beakers that each contain  liter.

There are 3 beakers that each contain  liter.

Multiply each amount of liquid by the number of beakers containing that amount.

Now, add the amounts to find the total amount of liquid in all the beakers.

Last, subtract the total amount of liquid from the amount that the container can hold, 4 liters.

So, after pouring all of the liquid into an empty container that can hold exactly 4 liters, the container can hold 1/2 liter more liquid.

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How to make 69% as a fraction in simplest form?
IceJOKER [234]
69% can be written as
69/100
That cannot be reduced any further since 69 and 100 do not have any common factors other than 1
4 0
3 years ago
What is the prime factorization of 28 and 50?<br> Explain if possible.
dangina [55]

Answer:

prime factorization of 28

28 = 2 × 2 × 7

prime factorization of 50

50 = 2 × 5 × 5

Step-by-step explanation:

GCF, multiply all the prime factors common to both numbers:

Therefore, GCF = 2

3 0
2 years ago
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Sofia made a scale drawing of a house. The scale she used was 1 millimeter : 6 meters. If the actual length of the garage is 12
romanna [79]

Answer:

2 millimeters.

Step-by-step explanation:

1 millimeter : 6 meters

x millimeters : 12 meters

x = (12÷6) × 1

x = 2×1

x = 2 millimeters

6 0
3 years ago
Every day your friend commutes to school on the subway at 9 AM. If the subway is on time, she will stop for a $3 coffee on the w
Shtirlitz [24]

Answer:

1.02% probability of spending 0 dollars on coffee over the course of a five day week

7.68% probability of spending 3 dollars on coffee over the course of a five day week

23.04% probability of spending 6 dollars on coffee over the course of a five day week

34.56% probability of spending 9 dollars on coffee over the course of a five day week

25.92% probability of spending 12 dollars on coffee over the course of a five day week

7.78% probability of spending 12 dollars on coffee over the course of a five day week

Step-by-step explanation:

For each day, there are only two possible outcomes. Either the subway is on time, or it is not. Each day, the probability of the train being on time is independent from other days. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

The probability that the subway is delayed is 40%. 100-40 = 60% of the train being on time, so p = 0.6

The week has 5 days, so n = 5

She spends 3 dollars on coffee each day the train is on time.

Probabability that she spends 0 dollars on coffee:

This is the probability of the train being late all 5 days, so it is P(X = 0).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(0.6)^{0}.(0.4)^{5} = 0.0102

1.02% probability of spending 0 dollars on coffee over the course of a five day week

Probabability that she spends 3 dollars on coffee:

This is the probability of the train being late for 4 days and on time for 1, so it is P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{5,1}.(0.6)^{1}.(0.4)^{4} = 0.0768

7.68% probability of spending 3 dollars on coffee over the course of a five day week

Probabability that she spends 6 dollars on coffee:

This is the probability of the train being late for 3 days and on time for 2, so it is P(X = 2).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{5,2}.(0.6)^{2}.(0.4)^{3} = 0.2304

23.04% probability of spending 6 dollars on coffee over the course of a five day week

Probabability that she spends 9 dollars on coffee:

This is the probability of the train being late for 2 days and on time for 3, so it is P(X = 3).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{5,3}.(0.6)^{3}.(0.4)^{2} = 0.3456

34.56% probability of spending 9 dollars on coffee over the course of a five day week

Probabability that she spends 12 dollars on coffee:

This is the probability of the train being late for 1 day and on time for 4, so it is P(X = 4).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{5,4}.(0.6)^{4}.(0.4)^{1} = 0.2592

25.92% probability of spending 12 dollars on coffee over the course of a five day week

Probabability that she spends 15 dollars on coffee:

Probability that the subway is on time all days of the week, so P(X = 5).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{5,5}.(0.6)^{5}.(0.4)^{0} = 0.0778

7.78% probability of spending 12 dollars on coffee over the course of a five day week

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On a coordinate plane, solid circles appear at the following points: (negative 3, negative 3), (negative 3, 2), (1, 1), (2, nega
FinnZ [79.3K]

Answer:

ITS (3-2.) Thank me later

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2 years ago
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