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ioda
3 years ago
9

PLEASE HELP ASAP- solve the equation : 9x^2+64=0 . i need work to be shown for credit ....

Mathematics
1 answer:
k0ka [10]3 years ago
6 0
In this quadratic equation a=9 b=0 c=64, you could use the Quadratic Formula:
x = [-b +-sqrt (b^2 -4*a*c)] / 2*a
x = 0 +- sqrt (0 -4*9*64) / 2*9
x = +- sqrt(-2,304) / 18

x = + 48 i / 18
x = -48 i /18

Where "i" is the square root of minus 1.


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The sum of two numbers is 54. The smaller number is 18 less than the larger number. What are the numbers?
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Answer:

The larger number is 37.  This makes the smaller number 56 - 37, which is 19.

Step-by-step explanation:

 

The first step is to pick variables for the two numbers.  Lets call the smaller number x and the larger number y.

Since the sum of the two numbers is 56, this means that x + y = 56.  Let's call this equation 1 and save it for later.

 

The next sentence says:

The smaller number is 18 less than the larger number.  So, 18 less than the larger number would be y - 18.  So, the smaller number must be equal to this, so

 

x = y - 18

 

Replace the x in equation 1 with y - 18

 

x + y = 56

(y-18) + y = 56   (replace x with y-18)

2y - 18 = 56        (add the y's)

2y = 74               (add 18 to both sides)

y = 37                 (divide both sides by 2)

 

So, the larger number is 37.  This makes the smaller number 56 - 37, which is 19.

 

Hope this helps!!  :)

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Step-by-step explanation:

hello :

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Correct answer:

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