I cant see the picture good can you write it out not in picture because it is blury for me I dont know about the others
Answer: Option 'c' is correct.
Step-by-step explanation:
Since we have given that
n = 1200
x = 32% of 1200
So, 
We need to find 95% confidence interval.
so, z = 1.96
So, margin of error would be

So, Interval would be

Hence, Option 'c' is correct.
16. 5x^3 y^-5 • 4xy^3
20x^4y^-2
20x^4 • 1/y^2
=20x^4/y^2
17. -2b^3c • 4b^2c^2
= -8b^5c^3
18. a^3n^7 / an^4 (a^3 minus a = a^2 same as n^7 minus n^4 = n^3)
=a^2n^3
19. -yz^5 / y^2z^3
= -z^2/y
20. -7x^5y^5z^4 / 21x^7y^5z^2 (divide -7 to 21 and minus xyz)
= -z / 3x^2
21. 9a^7b^5x^5 / 18a^5b^9c^3
=a^2c^2 / 2b^4
22. (n^5)^4
n ^5 x 4
=n^20
23. (z^3)^6
z ^3 x 6
=z^18
Answer:
(9159 / 7 = 1308.429)
Step-by-step explanation:
Simply multiply the last digit by 2 and then subtract the product from the remaining digits.
If that difference is divisible by 7, then 9159 is divisible by 7.
The last digit in 9159 is 9 and the remaining digits are 915. Thus, the math to determine if 9159 is divisible by 7 using our alternate method is:
915 - (9 x 2) = 897
Since 897 is not divisible by 7, 9159 is also not divisible by 7.
Therefore, the answer to "Is 9159 Divisible By 7?" is no.
(9159 / 7 = 1308.429)
Answer:
A-3, B-4, C-1, D-2
Step-by-step explanation:
A:
- 5x-(3x+1)
- Expand, 5x-3x-1
- Combine like terms, 2x-1
B:
- 5x-(-3x-1)
- Expand, 5x+3x+1
- Combine like terms, 8x+1
C:
- -5x-(3x+1)
- Expand, -5x-3x-1
- Combine like terms, -8x-1
D:
- -5x-(-3x-1)
- Expand, -5x+3x+1
- Combine like terms, -2x+1