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3 years ago

(-102.75)÷(-3) round to the nearest hundredth

Mathematics

1 answer:

Pani-rosa [81]3 years ago

6 0

Answer:34.17

Step-by-step explanation:

(-102.75) ➗ (-3)=34.17

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Guys pls help me!!!!!!!!

DENIUS [597]

Answer:

D. y = -x^2 + 1

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

If the work required to stretch a spring 2 ft beyond its natural length is 6 ft-lb, how much work is needed to stretch it 6 in.

mel-nik [20]

Answer:

0.375 feet-lb

Step-by-step explanation:

We have been given that the work required to stretch a spring 2 ft beyond its natural length is 6 ft-lb. We are asked to find the work needed to stretch the spring 6 in. beyond its natural length.

We can represent our given information as:

$6=\int\limits^2_0 {F(x)} \, dx$

We will use Hooke's Law to solve our given problem.

$F(x)=kx$

Substituting this value in our integral, we will get:

$6=\int\limits^2_0 {kx} \, dx$

Using power rule, we will get:

$6=\left[ \frac{kx^2}{2} \right ]^2_0$

$6=\frac{k(2)^2}{2}-\frac{k(0)^2}{2}$

$6=\frac{4k}{2}-0\\\\k=3$

We know that 6 inches is equal to 0.5 feet.

Work needed to stretch it beyond 6 inches beyond its natural length would be $\int\limits^{0.5}_0 {kx} \, dx =\int\limits^{0.5}_0 {3x} \, dx$

Using power rule, we will get:

$\int\limits^{0.5}_0 {3x} \, dx = \left [\frac{3x^2}{2}\right]^{0.5}_0$

$\frac{3(0.5)^2}{2}-\frac{3(0)^2}{2}\Rightarrow \frac{3(0.25)}{2}-0=\frac{0.75}{2}=0.375$

Therefore, 0.375 feet-lb work is needed to stretch it 6 in. beyond its natural length.

3 0

3 years ago

Ratio of the ages of three children is 2:5:1. The sum of their ages is 32 years. Find the ages of the youngest and the eldest

Hoochie [10]

Answer:the ages of the youngest and the eldest is 4 years and 20 Years respectively

Step-by-step explanation:

Ratio of the ages of three children is 2:5:1.

Total ratio =2+5+1=8

So that

the 1st Child's age =2/8 x 32=8 years

2nd Child's age =5/8 x 32= 20 years

3rd Child's age =1/8 x 32= 4 years

Therefore the ages of the youngest and the eldest is 4 years and 20 Years respectively.

6 0

3 years ago

Find the zeros of f(x)= x^2+ 2x – 8.<br> A. {1, 8}<br> B. {-2,4}<br> {2,-4}<br> D. {-1, -8)

givi [52]

f(x)= x^2+ 2x – 8

Factor the polynomial by finding 2 numbers that when added together would equal 2 and when multiplied together would equal -8.

The factored form is (x-2) (x+4)

Now find the zero's by solving for the two x's:

x = 2 and x = -4

The answer would be {2,-4}

8 0

3 years ago

First answer gets brainliest (worth 10 points) pls answer asap

AysviL [449]

Answer:

Step-by-step explanation:

(-2) ^-3 • (-2) ^4 = -2

-2^1 = -2

Hope this helps

6 0

3 years ago