3 years ago

Differentiate t²sin(2t)

Mathematics

1 answer:

dusya [7]3 years ago

4 0

Answer:

i am not sure what the answer is cause i have never had a question like this

Step-by-step explanation:

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Aleks04 [339]

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$x \: and \: 3x$

Then,

ATQ

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3 years ago

2x2 – 9x + 2 = –1

Reika [66]

Answer:

C) The discriminant is greater than 0, so there are two real roots

Step-by-step explanation:

<u>Discriminant</u>

$b^2-4ac\quad\textsf{when}\:ax^2+bx+c=0$

$\textsf{when }\:b^2-4ac > 0 \implies \textsf{two real roots}$

$\textsf{when }\:b^2-4ac=0 \implies \textsf{one real root}$

$\textsf{when }\:b^2-4ac < 0 \implies \textsf{no real roots}$

$2x^2-9x+2=-1$

$\implies 2x^2-9x+3=0$

$\implies a=2, b=-9, c=3$

$\begin{aligned}b^2-4ac &=(-9)^2-4(2)(3)\\& =81-24\\&=57 > 0\implies \textsf{two real roots}\end{aligned}$

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2 years ago

Differentiate t²sin(2t)​

Differentiate t²sin(2t)