The answer is: "<span>denitrification" .
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Answer:
temperature and whether they are polar or non-polar
Explanation:
Answer:
c. A to K
Explanation:
If the alanine mutation is restored to K or lysine residue, most likely the wild type level of activity can be restored. This is because, arginine and lysine have -NH2 as the functional group. So, functional similarity of arginine can be expected from lysine as well.
Hence the correct option is c that is A to K.
