Question

The sum of three consecutive odd numbers in 177. What is the largest of the three numbers?

Answer 1

Answer:

91 is the largest of the three numbers.

Step-by-step explanation:

Let the number be x, (x+2) and (x+4).

Given that the sum of these three odd consecutive numbers is 177.

$x+(x+2)+(x+4)=177$

$3x+6=177$

$3x=177-6$

$3x=171$

$x=\frac{171}{3}=57$

The number are : x = 57

(x+2) = 57 + 2 = 59

(x+4) = 57 +4 = 61

91 is the largest of the three numbers.

Answer 2

Answer:

1st odd  = 57

2nd odd  = 59

3rd odd  = 61

Step-by-step explanation:

Suppose the numbers to be:

1st odd = x -2

2nd odd = x

3rd odd = x +2

Now according to given conditions:

1st odd + 2nd odd + 3rd odd = 177

x - 2 + x +x + 2 = 177

By add -2 and + 2 will be cancelled

Adding all x

3x = 177

Dividing both sides by 3 we get

x = 177 / 3

x = 59

Now putting x = 59 to get three consecutive odds:

1st odd = x -2 = 59 - 2 = 57

2nd odd = x = 59

3rd odd = x +2 = 59 + 2 = 61

Proof:

1st odd + 2nd odd + 3rd odd = 177

57 + 59 + 61 = 177

177 = 177

hence proved

I hope it will help you!