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1 year ago

I keep getting D wrong

Mathematics

1 answer:

blondinia [14]1 year ago

3 0

Yeah d is wrong

:((( don’t know what it is supposed to be.

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1 year ago

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2 years ago

A study of long-distance phone calls made from General Electric Corporate Headquarters in Fairfield, Connecticut, revealed the l

Anna [14]

Answer:

a) 0.4452

b) 0.0548

c) 0.0501

d) 0.9145

e) 6.08 minutes or greater

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 4.7 minutes

Standard Deviation, σ = 0.50 minutes.

We are given that the distribution of length of the calls is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(calls last between 4.7 and 5.5 minutes)

$P(4.7 \leq x \leq 5.5) = P(\displaystyle\frac{4.7 - 4.7}{0.50} \leq z \leq \displaystyle\frac{5.5-4.7}{0.50}) = P(0 \leq z \leq 1.6)\\\\= P(z \leq 1.6) - P(z$

$P(4.7 \leq x \leq 5.5) = 44.52\%$

b) P(calls last more than 5.5 minutes)

$P(x > 5.5) = P(z > \displaystyle\frac{5.5-4.7}{0.50}) = P(z > 1.6)\\\\P( z > 1.6) = 1 - P(z \leq 1.6)$

Calculating the value from the standard normal table we have,

$1 - 0.9452 = 0.0548 = 5.48\%\\P( x > 5.5) = 5.48\%$

c) P( calls last between 5.5 and 6 minutes)

$P(4.7 \leq x \leq 5.5) = P(\displaystyle\frac{5.5 - 4.7}{0.50} \leq z \leq \displaystyle\frac{6-4.7}{0.50}) = P(1.6 \leq z \leq 2.6)\\\\= P(z \leq 2.6) - P(z$

$P(5.5 \leq x \leq 6) = 5.01\%$

d) P( calls last between 4 and 6 minutes)

$P(4 \leq x \leq 6) = P(\displaystyle\frac{4 - 4.7}{0.50} \leq z \leq \displaystyle\frac{6-4.7}{0.50}) = P(-1.4 \leq z \leq 2.6)\\\\= P(z \leq 2.6) - P(z$

$P(4 \leq x \leq 6) = 91.45\%$

e) We have to find the value of x such that the probability is 0.03.

P(X > x)

$P( X > x) = P( z > \displaystyle\frac{x - 4.7}{0.50})=0.03$

$= 1 -P( z \leq \displaystyle\frac{x - 4.7}{0.50})=0.03$

$=P( z \leq \displaystyle\frac{x - 4.7}{0.50})=0.997$

Calculation the value from standard normal z table, we have,

P(z < 2.75) = 0.997

$\displaystyle\frac{x - 4.7}{0.50} = 2.75\\x = 6.075 \approx 6.08$

Hence, the call lengths must be 6.08 minutes or greater for them to lie in the highest 3%.

8 0

2 years ago

Whats wrong with my answers?

malfutka [58]

77a)

$y=0.5x-2\implies y=\cfrac{x}{2}-2\implies \stackrel{x-intercept}{0=\cfrac{x}{2}-2} \\\\\\ 2=\cfrac{x}{2}\implies 4=x\qquad \qquad \boxed{(4~~,~~0)} \\\\\\ \stackrel{y-intercept}{y=0.5(0)-2}\implies y=-2\qquad \qquad \boxed{(0~~,~~-2)}$

77b)

$y=-0.4x+2\implies y=-\cfrac{4x}{10}+2\implies y=\cfrac{2x}{5}+2 \implies \stackrel{x-intercept}{0=\cfrac{2x}{5}+2} \\\\\\ -2=\cfrac{2x}{5}\implies -10=2x\implies \cfrac{-10}{2}=x\implies -5=x~\hfill \boxed{(-5~~,~~0)} \\\\\\ \stackrel{y-intercept}{y=-0.4(0)+2}\implies y=2\qquad \qquad \boxed{(0~~,~~2)}$

8 0

1 year ago