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lina2011 [118]
3 years ago
5

Name one bacterium that will appear as Gram positive coccus after the Gram stain?

Biology
1 answer:
jek_recluse [69]3 years ago
3 0

Answer:

staphylococci

Explanation:

Gram stain -

it is the method of staining which classify  the species of the bacteria into gram - positive and gram - negative .

This method distinguish the bacteria by its physical and chemical properties of the cell well of the bacteria .

1. In case of gram - positive , the stain is of color violet , because  to its thick cell wall .

and ,

2. In case of gram - negative , the stain is of pink color , because to thinner cell wall .

The bacterium , which shows Gram - positive coccus after the gram stain is staphylococci .

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In gorillas, the ability to roll the tongue is under the control of 1 gene. The R allele, which confers tongue-rolling ability,
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Answer:

0.4550

Explanation:

In this example, R allele is dominant, so individuals RR and Rr can roll their tongues. If in a population of 1000 gorillas, there are 575 gorillas who can roll their tongues, they will be RR and Rr.

In this case, there is Hardy Weinberg Equilibrium, so the following will be true:

p^{2}+2pq+q^{2}=1

Where:

p^{2}= frequency of RR

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q^{2}= frequency of rr

The question is what is the frequency of heterozygotes, or, what is the value of 2pq.

We know that RR+Rr is 575 individuals in a population of 1000, or 0.575.

In other words:

p^{2}+2pq=0.575

So, it is possible to find q^{2}:

q^{2}= 1-2pq-p^{2}  \\q^{2}=1-(0.575)\\q^{2}=0.425

Now, there are two alleles in the population, so the following will be true:

p+q=1

It is possible to find q  (the frequency of allele r) and p (the frequency of allele p):

q=\sqrt{q^{2} }\\ q=\sqrt{0.425} \\q=0.652

Therefore:

p=1-q\\p=1-0.652\\p=0.348

Now, the frequency of heterozygotes or 2pq is:

2pq=2*0.652*0.348\\2pq=0.45

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