The correct answer is E)52
When there is Hardy-Weinberg equilibrium like in this case of a single locus with two alleles denoted A and a with frequencies f(A) = p and f(a) = q, the expected genotype frequencies under random mating are f(AA) = p² for the AA homozygotes, f(aa) = q² for the aa homozygotes, and f(Aa) = 2pq for the heterozygotes. Let's put that A is dominant and a is recessive allele. In Hardy-Weinberg equilibrium we have:
p²+2*p*q+q²= 1 p+q=1 p=1-q
f(a) =0.4=q q²=0.4²=0.16=16%
p= 1-0.4=0.6 p²=0.6²=0.36=36%
Percentage of a homozygous genotype in the population is 16%+36%=52%
Answer: Energy
Explanation:
If there is no chemical bonds in the substance or the bonds in the substances are so strong so there would be no energy released.
This is because there is a need of energy when any bond is formed and energy is released when bonds are broken down.
Energy is stored in the bonds which is released when bonds are broken down.
There would be no energy available for various processes and no movement of energy will take place.
For the answer to the question above, the Endocytosis is a process that allows a cell to engulf molecules in the entirety of the molecule and surround those molecules in a membrane. Transport is when a small molecule <span>can actively transport through a cellular membrane and come out again. I hope this helps</span>
Answer:
Rough endoplasmic reticulum differ from smooth endoplasmic reticulum by the presence and absence of ribosomes in their surface.
Explanation:
Rough endoplasmic is named so because RER contain ribosomes at their surface and due to the presence of ribosomes rough endoplasmic reticulum play an importnt role in protein synthesis or translation.
Whereas smooth endoplasmic reticulum does not contain any ribosome in its surface.smooth endoplasmic reticulum helps in the biosynthesis of lipid and steroids along with detoxification of toxic compounds.
