Answer:
23.1 or 18+√26 units.
Step-by-step explanation:
First, you would find the distance of AB which is you can just count because it is a straight line: 7 units. Just skip BC for now, I'll come back to it later. To find CD, you do the same thing and would get 6 units. Then, for DA or AD you do it again and get 5. Now for BC you would use the distance formula, if you do not know this yet, I will have a different method below this.
The distance formula is : d=√((x₂-x₁)²+(y₂-y₁)²) Now X₂ would be the x-coordinate of B which is 4. X₁ would be the x-coordinate of C which is 3. Y₂ would be the y-coordinate of B which is 2 while Y₁ is the y-coordinate of C which would be -3. Finally you plug this into the equation which would be d=√((4-3)²+(2-(-3))²) which equals √26 or 5.1 if you round it. Finally, you would add all the side lengths which would be 7, 6, 5 and 5.1 or √26. Which gets you 23.1 or 18+√26 units.
Now if you don't know the distance formula, you would use the pythagorean theorem. First, you would draw an imaginary straight line down from point B to the same y-coordinate as C, getting you to the point (4,-3). The distance from B to that point would be 5 units. Then you draw another imaginary line from point C to (4,-3) . The distance from that would be 1. Now, you can use the pythagorean theorem with BC being the hypotenuse and 5 and 1 being the legs. 5²+1²=c². c²=26 c=√26
