Answer:
The word "ARRANGE" can be arranged in
2!×2!
7!
=
4
5040
=1260 ways.
For the two R's do occur together, let us make a group of R's taking from "ARRANGE" and permute them.
Then the number of ways =
2!
6!
=360.
The number ways to arrange "ARRANGE", where two "R's" will not occur together is =1260−360=900.
Also in the same way, the number of ways where two "A's" are together is 360.
The number of ways where two "A's" and two "R's" are together is 5!=120.
The number of ways where neither two "A's" nor two "R's" are together is =1260−(360+360)+120=660.
Step-by-step explanation:
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16 because 2•0 is 0. 8-0 is 8 and 2(8) is 16
Think of it as (-4x+1)(3x+2) then distribute: -4x x 3x= -12x^2, -4x x 2= -8x, 1 x 3x = 3x, and 2 x 1=2. put together all the answers we just got so: -12x^2 - 8x +3x +2 then simplify to get -12x^2 -5x +2
No it is not a function, because a function cannot have more than one output per input. When x=-3, there are two solutions shown: (-3,2) and (-3,3), therefore it cannot be a function.
<span>
f(x)= −3/5x³</span><span>
The domain is all values x can be. There are no restrictions on x. it can be any real number (-∞ , ∞)
The range is all values y can be. There are noi restrictions on y either because the function is odd. y is </span><span>(-∞ , ∞)
The best answer is D.
domain (-∞, 0] ∪[0, ∞)
range </span><span>(-∞, 0] ∪[0, ∞) </span>