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3 years ago

In ΔUVW, the measure of ∠W=90°, the measure of ∠U=19°, and WU = 85 feet. Find the length of VW to the nearest tenth of a foot.

Mathematics

2 answers:

HACTEHA [7]3 years ago

8 0

Answer:

29.3feet

Step-by-step explanation:

In ΔUVW, the measure of ∠W=90°, the measure of ∠U=19°, and WU = 85 feet. Find the length of VW to the nearest tenth of a foot.

From the triangle given

<W = 90 degrees

<U = 19 degrees

<V = 180 - (90+19)

<V = 180 - 109

<V = 71 degrees

Using SOH CAH TOA

tan theta = opp/adj

tan <V = WU/VW

tan 71 = 85/VW

VW = 85/tan 71

VW = 85/2.9042

VW = 29.27

Hence the length of VW to the tenth of a foot is 29.3feet

raketka [301]3 years ago

4 0

29.3 is in fact the correct answer

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andrey2020 [161]

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1 year ago

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monitta

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2 years ago

Read 2 more answers

polygon A i simllar to polgon B. find the perimeer of polygon B if one side of polygon A is 24 A sde to polygon B is 15 and the

Gemiola [76]

Answer:

Perimeter of polygon B = 80 units

Step-by-step explanation:

Since both polygons are similar, their corresponding sides and perimeters are proportional. Knowing this we can setup a proportion to find the perimeter of polygon B.

$\frac{side-polygonA}{side-polygonB} =\frac{perimeter-polygonA}{perimeter-polygonB}$

Let $x$ be the perimeter of polygon B. We know from our problem that the side of polygon A is 24, the side of polygon B is 15, and the perimeter of polygon A is 128.

Let's replace those value sin our proportion and solve for $x$ :

$\frac{side-polygonA}{side-polygonB} =\frac{perimeter-polygonA}{perimeter-polygonB}$

$\frac{24}{15} =\frac{128}{x}$