All categories

3 years ago

Solve “X^2 -4x+5 using the discriminant formula b^2-4AC

Mathematics

1 answer:

aksik [14]3 years ago

8 0

Answer:

a= 1

b= -4

c = 5

(-4)^2 - 4(1)(5)

16-20= -4 no solution

You might be interested in

What is the value of the expression 2 + 7 + 49 - 6)2 + 6?

valentina_108 [34]

Answer:

=52

Step-by-step explanation:

easy

4 0

3 years ago

Read 2 more answers

This don’t make no sense anyone understand and if u do help plz

Bingel [31]

1. x = 0 and y = 3

2. x = 2 and y = 7

3. x = 3 and y = 9

4. x = 5 and y = 13

7 0

3 years ago

The length of a rectangle is 1 more than 3 times the width . If the perimeter of the rectangle is 18 units , what’s it’s area?

nika2105 [10]

Answer:

14 square units

Step-by-step explanation:

You need to know the formulas for the perimeter of a rectangle and the area of a rectangle, which are

2L + 2W - P where L is the length, W is the width, and P is the perimeter

and

A = LW

So we need to find the length and width to find the area

Step 1: Write equations out of the given information

"The length of a rectangle is 1 more than 3 times the width" can be rewritten as

L = 3W + 1

"the perimeter of the rectangle is 18 units" can be rewritten as

2L + 2W = 18

Step 2: Plug the first formula into the second one and solve

2(3W + 1) + 2W = 18

Simplify...

6W + 2 + 2W = 18

Combine like terms and subtract 2 from both sides

8W = 16

Divide both sides by 8 to isolate the W

W = 2

Step 3:

Plug W = 2 into the formula for L and solve for L

L = 3(2) + 1

L = 6 + 1

L = 7

Step 4: Use the length and width to calculate the area

A = LW

A = (7)(2)

A = 14 units squared

6 0

4 years ago

Get fit gym charges a yearly fee of $250 plus $10 for each session with a personal trainer. Tight N’Toned gym charges a one time

Sindrei [870]

Answer:12345678910

Step-by-step explanation:

8 0

3 years ago

Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

5 0

3 years ago