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belka [17]
3 years ago
10

PLEASE HELP with the image below

Mathematics
1 answer:
ki77a [65]3 years ago
7 0
The formula for volume of a pyramid is V = 1/3 bh. If we plug everything into the formula, you should get an answer of 17cm cubed. Hope this helps!
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When u are doing math and u have a question with pi in it don't u use "3.14" or do u use "3.141" or is it "3.14159?
Tju [1.3M]
Usually, I use 3.14.
7 0
3 years ago
Read 2 more answers
For what value of mc009-1 is the function one-to-one?
exis [7]

Using the concept of an one-to-one function, it will be one-to-one for c = 13.

<h3>What is an one-to-one function?</h3>

A function is said to be one-to-one if each output is mapped to only one input.

In this problem, outputs 2, 5 and 11 have already been matched to inputs 1, 3 and 5, respectively, hence the output for input 6 has to be c = 13 for a one-to-one function.

More can be learned about one-to-one functions at brainly.com/question/10853542

#SPJ1

4 0
1 year ago
Given that P = (5, 8) and Q = (6, 9), find the component form and magnitude of vector PQ.
max2010maxim [7]

Answer:

<1 ,1>..., square root of two

Step-by-step explanation:

Component of vector PQ...,

; Q - P...where you subtract the x coordinate of Q by the x coordinate of P and the same for the y coordinate

; <(6-5),(9-8)>

; < 1,1 >

And the magnitude of PQ...,

;square root of( 1^2 + 1^2 )

;square root of 2

3 0
3 years ago
Find a formula for the described function. an open rectangular box with volume 9 m3 has a square base. express the surface area
Maru [420]

Let

x--------> the length side of the square base

h--------> the height of the box

we know that

<u>the volume of the box is equal to</u>

V=x^{2} *h\\ V=9\ m^{3}

so

x^{2} *h=9\\\\h=\frac{9}{x^{2} }

<u>the surface area of the box is equal to</u>

SA=area\ of\ the\ base+perimeter\ of\ base*height (remember that the box is open)

area of the base=(x^{2})\ m^{2}

Perimeter of the base=(4*x)\ m

height=(h) m

h=\frac{9}{x^{2}}

substitute

SA=x^{2} +4*x*h\\ \\ \\ SA=x^{2} +4*x*\frac{9}{x^{2} } \\ \\ SA=x^{2} +\frac{36}{x}

we know that

the value of x can not be negative and the denominator can not be zero

therefore

<u>the answer is</u>

the domain of  SA is x> 0

the domain is the interval-------------> (0,∞)

6 0
2 years ago
Which value for x makes the sentence true?
Kipish [7]
I hope this helps you out

8 0
3 years ago
Read 2 more answers
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