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svlad2 [7]
3 years ago
12

Suppose $1,000 is borrowed for one year at 8% simple interest. How much is due at the end of the year to

Mathematics
2 answers:
IceJOKER [234]3 years ago
8 0

Answer:

You would not have mney at all.

Step-by-step explanation:

AleksAgata [21]3 years ago
6 0

Answer:

you will be bankrupt simple!

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Heather, Shen, and Aldo served a total of 57 orders Monday at the school cafeteria. Shen served 2 times as many as Aldo. Aldo se
pishuonlain [190]

Answer:

Shen served 32 orders, Aldo served 16 orders and Heather served 9 orders

Step-by-step explanation:

Let S represent Shen, A, Aldo and H, Heather

Now, let's interpret the question

Shen served 2 times as many as Aldo, this gives:

S = 2A          ...eq 1

Aldo served 7 more orders than Heater

A = 7 + H     ... eq 2

Slot in the value of A in eq 1

Therefore,

S = 2 (7 + H)

Expand the bracket

S = 14 + 2H

Shen, Heather and Aldo served a total of 57 orders

S + A + H = 57

Slot in the values of S and A

(14 + 2H) + (7 + H) + H = 57

14 + 2H + 7 + H + H = 57

Collect like terms

14 + 7 + 2H + H + H = 57

21 + 4H = 57

4H = 57 - 21

4H = 36

H = 9

Substitute the value of eq 2

A = 7 + H

A = 7 + 9

A = 16

Substitute the value of A in eq 1

S = 2A

S = 2(16)

S = 32

Therefore, Shen served 32 orders, Aldo served 16 orders and Heather served 9 orders

5 0
3 years ago
What is the measure of b?
sergejj [24]

Answer:

mesure of b is what hahhahaha

5 0
3 years ago
7 and a number equals 21​
torisob [31]

Answer:

7x3=21

Step-by-step explanation:

7+7+7=21, 7x3=21

5 0
2 years ago
When Klorina swims with the current, she swims 10 km in 2 h. Against the current, she can swim only 8 km in the same time. How f
nasty-shy [4]

Answer:

Klorina's rate in still water is 4.5 km/h

Current's rate is 0.5 km/h

Step-by-step explanation:

Let

x km/h = Klorina's rate in still water

y km/h = current's rate

<u>With the current (current helps):</u>

Distance = 10 km

Time = 2 hours

Rate = x + y km/h

10=2(x+y)

<u>Against the current:</u>

Distance = 8 km

Time = 2 hours

Rate = x - y km/h

8=2(x-y)

Divide both equations by 2:

x+y=5\\ \\x-y=4

Add these equations:

x+y+x-y=5+4\\ \\2x=9\\ \\x=4.5\ km/h

Subtract these two equations:

(x+y)-(x-y)=5-4\\ \\x+y-x+y=1\\ \\2y=1\\ \\y=0.5\ km/h

4 0
2 years ago
Urgent!! Will mark brainliest!!
horsena [70]

Answer:

1) x is negative and y is positive ⇒ last answer

2) cotФ = -12/35 ⇒ second answer

3) The right identity is cot²Ф - csc²Ф = -1 ⇒ last answer

Step-by-step explanation:

* For any point (x , y) lies on the terminal side of the angle Ф

 in standard position

* x = cosФ and y = sinФ

- If Ф in the first quadrant, then x , y are positive

∴ All trigonometry functions are positive

- If Ф in the second quadrant, then x is negative , y is positive

∴ sinФ only is positive

- If Ф in the third quadrant, then x is negative , y is negative

∴ tanФ only is positive

- If Ф in the fourth quadrant, then x is positive , y is negative

∴ cosФ only is positive

* Lets solve the problems

∵ Ф = 3π/4 ⇒ (135°)

∴ It lies on the second quadrant

∴ x is negative and y is positive

* Lets revise the reciprocal of sinФ, cosФ and tanФ

- cscФ = 1/sinФ

- secФ = 1/cosФ

- cotФ = 1/tanФ

∵ secФ = -37/12

∴ cosФ = -12/37

∵ π/2 < Ф < π

∴ Ф lies on the second quadrant

∴ cotФ is negative values

∵ tan²Ф = sec²Ф - 1

∵ secФ = -37/12

∴ tan²Ф = (-37/12)² - 1 = 1225/144 ⇒ take√ for both sides

∴ tanФ = ± 35/12

∵ cotФ = ± 12/35

∵ cotФ is negative value

∴ cotФ = -12/35

* In the standard position of the angle Ф the terminal

 of it lies on the unit circle O

- By using Pythagorean theorem

∵ x² + y² = 1

∵ x = cosФ and y = sinФ

∴ cos²Ф + sin²Ф = 1 ⇒ (1)

∴ cos²Ф = 1 - sin²Ф

∴ sin²Ф = 1 - cos²Ф

* Divide (1) by cos²Ф

∴ cos²Ф/cos²Ф + sin²Ф/cos²Ф = 1/cos²Ф

* Remember sin²Ф/cos²Ф = tan²Ф and 1/cos²Ф = sec²Ф

∴ 1 + tan²Ф = sec²Ф ⇒ (2) ⇒ subtract 1 from both sides

∴ tan²Ф = sec²Ф - 1 ⇒ subtract sec²Ф from both sides

∴ tan²Ф - sec²Ф = -1

* Divide (1) by sin²Ф

∴ cos²Ф/sin²Ф + sin²Ф/si²Ф = 1/sin²Ф

* Remember cos²Ф/sin²Ф = cot²Ф and 1/sin²Ф = csc²Ф

∴ cot²Ф + 1 = csc²Ф ⇒ (3) ⇒ subtract 1 from both sides

∴ cot²Ф = csc²Ф - 1 ⇒ subtract csc²Ф from both sides

∴ cot²Ф - csc²Ф = -1

* The right identity is cot²Ф - csc²Ф = -1

3 0
3 years ago
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