Answer:
Write and evaluate the expression. Then, complete the statements.
A 1-column table with 5 rows. Column 1 is labeled Multiplication Words with entries double, multiply, product, twice, times.
Yuna ran three times as many kilometers.
Evaluate when k = 12.2.
First, write the expression as
✔ 3k
.
Second,
✔ substitute
12.2 in for the variable, k.
Third,
✔ simplify
by
✔ multiplying
3 and 12.2.
The answer is
✔ 36.6
Let X be the number of burglaries in a week. X follows Poisson distribution with mean of 1.9
We have to find the probability that in a randomly selected week the number of burglaries is at least three.
P(X ≥ 3 ) = P(X =3) + P(X=4) + P(X=5) + ........
= 1 - P(X < 3)
= 1 - [ P(X=2) + P(X=1) + P(X=0)]
The Poisson probability at X=k is given by
P(X=k) = 
Using this formula probability of X=2,1,0 with mean = 1.9 is
P(X=2) = 
P(X=2) = 
P(X=2) = 0.2698
P(X=1) = 
P(X=1) = 
P(X=1) = 0.2841
P(X=0) = 
P(X=0) = 
P(X=0) = 0.1495
The probability that at least three will become
P(X ≥ 3 ) = 1 - [ P(X=2) + P(X=1) + P(X=0)]
= 1 - [0.2698 + 0.2841 + 0.1495]
= 1 - 0.7034
P(X ≥ 3 ) = 0.2966
The probability that in a randomly selected week the number of burglaries is at least three is 0.2966
First you take 15/10 and see that you can take 5 out of the top and bottom, so it would become 3/2. Now you have 2 3/2. 2 goes into 3 once with 1 remainder so 3/2= 1 1/2
So then you take the original 2 and add it to 1 1/2. The answer is now 3 1/2
1) 4x + 3(x-9) = 19
or, 4x + 3x - 27 = 19
or, 7x = 19+27
or, 7x = 46
or, x = 46/7
◆ x = 6.57
2) 2(x-4) + 5x = 3
or, 2x - 8 + 5x = 3
or, 7x = 3+8
or, x = 11/7
◆ x = 1.57
3) 60 = 8y - 3(y-10)
or, 60 = 8y - 3y + 30
or, 60 - 30 = 5y
or, y = 30/5
◆ y = 6
4) 40 + 3c = 3 + 9(c-2)
or, 40 + 3c = 3 + 9c - 18
or, 40 + 3c = 9c - 15
or, 9c - 3c = 40 + 15
or, 6c = 55
◆ c = 9.166
I hope you understand..
Thank you...♥♥
