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2 years ago

How do I find the missing sides in this triangle?

Mathematics

1 answer:

stiv31 [10]2 years ago

6 0

Answer:

This is a 30-60-90 triangle so you would do this formula:

Short side (opposite the 30 degree angle) = x.

Hypotenuse (opposite the 90 degree angle) = 2x.

Long side (opposite the 60 degree angle) = x√3.

Step-by-step explanation:

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What is the square root of 1,567?

MakcuM [25]

39.5854 (this answer is rounded)

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2 years ago

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Solve for c of the right triangle

Ede4ka [16]

In order to solve this triangle we must use cosine law:
$c^{2} = a^{2} + b^{2} - 2ab*cosC$

Now let's plug in the values we are given:
$c^{2} = 5^{2} + 8^{2} - 2(5)(8) * cos 67$
$c^{2} = 25 + 64 - 80*cos67$
$c = \sqrt{80-cos67}$

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3 years ago

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Which polynomial correctly combines the like terms and puts the given polynomial in standard form?

Minchanka [31]

Answer: $-5x^3y^3+8x^4y^2-7xy^5+x^2y^4+8x^6$

Step-by-step explanation:

$-5x^3y^3+8x^4y^2-xy^5-2x^2y^4+8x^6+3x^2y^4-6xy^5$

$-5x^3y^3+8x^4y^2+(-xy^5-6xy^5)+(-2x^2y^4+3x^2y^4)+8x^6$

$-5x^3y^3+8x^4y^2+(-7xy^5)+(x^2y^4)+8x^6$

$-5x^3y^3+8x^4y^2-7xy^5+x^2y^4+8x^6$

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3 years ago

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Given f(x)= 3x+21. A. F(4)=B. F(X)= 50, X=2. C. F(-5)=D. F(X)= -34, X=

nignag [31]

The given function is

$f(x)=3x+2$

A . f(4) means we have to evaluate the function when x = 4.

$f(4)=3(4)+2=12+2=14$ <h2>Therefore, f(4) = 14.</h2>

B. f(x) = 50 means we have to evaluate the function when y = 50.-

$\begin{gathered} 50=3x+2 \\ 50-2=3x \\ x=\frac{48}{3} \\ x=16 \end{gathered}$ <h2>Therefore, f(16) = 50.</h2>

C. f(-5) means we have to evaluate the function when x = -5.

$f(-5)=3(-5)+2=-15+2=-13$ <h2>Therefore, f(-5) = -13.</h2>

D. f(x) = -34.

$\begin{gathered} -34=3x+2 \\ -34-2=3x \\ x=\frac{-36}{3} \\ x=-12 \end{gathered}$ <h2>Therefore f(-12) = -34.</h2>

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1 year ago

write an equation in point slope form of the line that passes through the point (-8,-2) and had a slope of m=5

Ede4ka [16]

Answer:

5x - y + 38 = 0

Step-by-step explanation:

solution:

slope(m) = 5

(x1 , y1) = (-8 , -2)

we know that,

(y - y1) = m(x -x1)

or, (y - -2) = 5(x - -8)

or, y+2 = 5(x + 8)

or, y+2 = 5x +40

or, 5x - y + 38 = 0 is the required equation

3 0

2 years ago